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3 years ago

Use the row of numbers shown below to generate 12 random numbers between 01 and 99.

Mathematics

1 answer:

sattari [20]3 years ago

6 0

Answer:

Below is the complete step-by-step explanation.

Step-by-step explanation:

Given the row of numbers

25060 12315 86244 97348 36173 32710 80033 16160

Taking 25060 as seed

Total random numbers to be generates = 12

Range of random number generators

Minimum value = 01
Maximum Value = 99

Seed the number (25060) into your calculator. 25060 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

85 90 62 45 26 97 40 55 67 17 10 32

Taking 12315 as seed

Total random numbers to be generates = 12

Range of random number generators

Minimum value = 01
Maximum Value = 99

Seed the number (12315) into your calculator. 12315 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

33 20 26 68 73 09 46 14 82 74 17 04

Taking 86244 as seed

Total random numbers to be generates = 12

Range of random number generators

Minimum value = 01
Maximum Value = 99

Seed the number (86244) into your calculator. 86244 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

54 93 02 50 37 01 86 51 38 28 23 36

Taking 97348 as seed

Total random numbers to be generates = 12

Range of random number generators

Minimum value = 01
Maximum Value = 99

Seed the number (97348) into your calculator. 97348 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

04 79 01 86 51 02 50 37 38 28 23 36

Taking 36173 as seed

Total random numbers to be generates = 12

Range of random number generators

Minimum value = 01
Maximum Value = 99

Seed the number (36173) into your calculator. 36173 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

13 03 28 17 14 31 98 47 40 48 68 19

Taking 32710 as seed

Total random numbers to be generates = 12

Range of random number generators

Minimum value = 01
Maximum Value = 99

Seed the number (32710) into your calculator. 32710 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

22 80 42 03 27 89 98 46 14 31 72 56

Taking 80033 as seed

Total random numbers to be generates = 12

Range of random number generators

Minimum value = 01
Maximum Value = 99

Seed the number (80033) into your calculator. 80033 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

29 86 51 01 23 64 37 36 35 72 14 59

Taking 16160 as seed

Total random numbers to be generates = 12

Range of random number generators

Minimum value = 01
Maximum Value = 99

Seed the number (16160) into your calculator. 16160 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

93 54 72 58 30 14 48 87 99 95 83 29

Keywords: random number generator

Learn more about random number generator from brainly.com/question/1601128

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Answer-

a. Probability that three of the candies are white = 0.29

b. Probability that three are white, 2 are tan, 1 is pink, 1 is yellow, and 2 are green = 0.006

Solution-

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The number of ways we can do the same process =

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As we have to draw total of 9 candies, after 3 white candies we left with 9-3 = 6, candies. And those 6 candies have to be selected from 52-19 = 33 candies, (as we are drawing candies other than white, so it is subtracted)

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Total number of ways of selecting 3 whites, 2 are tans, 1 is pink, 1 is yellow, and 2 are greens is,

$\binom{19}{3} \binom{10}{2} \binom{7}{1} \binom{5}{1} \binom{6}{2}$

$=(\frac{19!}{3!16!}) (\frac{10!}{2!8!}) (\frac{7!}{1!6}) (\frac{5!}{1!4!}) (\frac{6!}{2!4!})$

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$\binom{52}{9}=\frac{52!}{9!43!} =3679075400$

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