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vitfil [10]
3 years ago
15

Use the row of numbers shown below to generate 12 random numbers between 01 and 99.

Mathematics
1 answer:
sattari [20]3 years ago
6 0

Answer:

Below is the complete step-by-step explanation.

Step-by-step explanation:

Given the row of numbers

25060 12315 86244 97348 36173 32710 80033 16160

<u>Taking 25060 as seed</u>

Total random numbers to be generates = 12

Range of random number generators

  • Minimum value = 01
  • Maximum Value = 99

Seed the number (25060) into your calculator. 25060 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

85 90 62 45 26 97 40 55 67 17 10 32

<u>Taking 12315 as seed</u>

Total random numbers to be generates = 12

Range of random number generators

  • Minimum value = 01
  • Maximum Value = 99

Seed the number (12315) into your calculator. 12315 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

33 20 26 68 73 09 46 14 82 74 17 04

<u>Taking 86244 as seed</u>

Total random numbers to be generates = 12

Range of random number generators

  • Minimum value = 01
  • Maximum Value = 99

Seed the number (86244) into your calculator. 86244 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

54 93 02 50 37 01 86 51 38 28 23 36

<u>Taking 97348 as seed</u>

Total random numbers to be generates = 12

Range of random number generators

  • Minimum value = 01
  • Maximum Value = 99

Seed the number (97348) into your calculator. 97348 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

04 79 01 86 51 02 50 37 38 28 23 36

<u>Taking 36173 as seed</u>

Total random numbers to be generates = 12

Range of random number generators

  • Minimum value = 01
  • Maximum Value = 99

Seed the number (36173) into your calculator. 36173 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

13 03 28 17 14 31 98 47 40 48 68 19

<u>Taking 32710 as seed</u>

Total random numbers to be generates = 12

Range of random number generators

  • Minimum value = 01
  • Maximum Value = 99

Seed the number (32710) into your calculator. 32710 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

22 80 42 03 27 89 98 46 14 31 72 56

<u>Taking 80033 as seed</u>

Total random numbers to be generates = 12

Range of random number generators

  • Minimum value = 01
  • Maximum Value = 99

Seed the number (80033) into your calculator. 80033 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

29 86 51 01 23 64 37 36 35 72 14 59

<u>Taking 16160 as seed</u>

Total random numbers to be generates = 12

Range of random number generators

  • Minimum value = 01
  • Maximum Value = 99

Seed the number (16160) into your calculator. 16160 ➡️ rand

So, the operation randInt(1,99,12) will generate the following 12 random numbers between 01 and 99.

93 54 72 58 30 14 48 87 99 95 83 29

Keywords: random number generator

Learn more about random number generator from brainly.com/question/1601128

#learnwithBrainly

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ivanzaharov [21]

Answer:

  • Option A

Step-by-step explanation:

A'B' is 1/2 times the AB as the scale factor is 1/2.

<u>Find the length of AB using distance formula.</u>

  • AB = \sqrt{(4 - 2)^2 + (4-0)^2}  = \sqrt{20}  = 2\sqrt{5}

<u>And find A'B':</u>

  • A'B' = 1/2*2\sqrt{5}  = \sqrt{5}

Correct choice is A

8 0
3 years ago
PLEASE HELP ASAP! THANK YOU
Dafna1 [17]

Answer:

39 m.

Step-by-step explanation:

The area of a triangle is calculated by the expression given as:

Area = bh/2

where b is the base and h is the height.

We calculate as follows:

270 = b (15) / 2

b = 36

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4 0
3 years ago
Only one of the comparisons below is correct. Which is correct? What benchmark was used in your answer?
tiny-mole [99]

Answer:

2/3<9/10; I used 3/4 as a benchmark.

Step-by-step explanation:

2/3<1/2; I used 1/2 as a benchmark.

2/3 = 0.(20/3) = 0.667

1/2 = 0.(10/2) = 0.5

So this is wrong, as 0.667 > 0.5.

1/2=3/5; I used 1/4 as a benchmark.

1/2 = 0.(10/2) = 0.5

3/5 = 0.(30/5) = 0.6

0.5 != 0.6, so this is wrong.

2/3<9/10; I used 3/4 as a benchmark.

2/3 = 0.(20/3) = 0.667

9/10 = 0.(90/10) = 0.9

So this is correct, as 0.667 < 0.9

3/4<2/3; I used 1/2 as a benchmark.

3/4 = 0.(30/4) = 0.75

2/3 = 0.(20/3) = 0.667

0.75 > 0.667, so this is wrong.

5 0
3 years ago
Find the value of h(-7) for the function below.
vovikov84 [41]

Answer:

  B.  138.7

Step-by-step explanation:

Put the given number where the variable is and do the arithmetic.

  h(x) = 5.7 -19x

  h(-7) = 5.7 -19(-7) = 5.7 +133 = 138.7

6 0
3 years ago
Read 2 more answers
HELP ME Using the following equation, complete the square and find the center and radius of the circle:
IrinaK [193]

Answer: (-2,3), r=5\ \text{units}

Step-by-step explanation:

Given

the equation is x^2+y^2+4x-6y-12=0

completing the square

\Rightarrow (x^2+2\times 2\times x+4-4)+(y^2-2\times3\times y+9-9)-12=0\\\Rightarrow (x^2+2\times 2\times x+4)+(y^2-2\times3\times y+9)-12-4-9=0\\\Rightarrow (x+2)^2+(y-3)^2=25\\\Rightarrow (x+2)^2+(y-3)^2=5^2\\\Rightarrow (x-(-2))^2+(y-3)^2=5^2

Thus, the center of the circle is (-2,3) and radius is r=5\ \text{units}

5 0
3 years ago
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