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Licemer1 [7]
2 years ago
10

Factor the given polynomial completely. a²-4a-32

Mathematics
2 answers:
MrRa [10]2 years ago
8 0

Step-by-step explanation:

a²-8a+4a-32

a(a-8)+4(a-8)

(a+4)(a-8)

zhuklara [117]2 years ago
7 0

Answer:

(x + 4)(x - 8).

Step-by-step explanation:

a²-4a-32

We need 2 numbers whose product is -32 and whose sum is -4.

They are +4 and -8, so the factors are:

(x + 4)(x - 8).

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What is the value of x in the equation 8 + x = 3? (4 points)
ozzi

Answer:

x=-5

Step-by-step explanation:

8+x=3

Subtract 8 from both sides of the equation.

x=-5

HTH :)

6 0
3 years ago
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If 60 of the 200 students are girls, then what percent of the students are girls?
OlgaM077 [116]
30%?
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If tanA+sinA=m and tanA-sinA=n.prove that m^2-n^2=4√mn
mash [69]

Let a=\tan A and b=\sin A. Then

m^2-n^2=(a+b)^2-(a-b)^2=(a^2+2ab+b^2)-(a^2-2ab+b^2)=4ab

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and

mn=(a+b)(a-b)=a^2-b^2

\implies4\sqrt{mn}=4\sqrt{\tan^2A-\sin^2A}

The expression under the square root can be rewritten as

\tan^2A-\sin^2A=\dfrac{\sin^2A}{\cos^2A}-\sin^2A=\sin^2A\left(\dfrac1{\cos^2A}-1\right)=\sin^2A(\sec^2A-1)

Recall that

\sin^2A+\cos^2A=1\implies\tan^2A+1=\sec^2A

so that

\tan^2A-\sin^2A=\sin^2A\tan^2A

and assuming \sin A>0 and \tan A>0, we end up with

4\sqrt{\tan^2A-\sin^2A}=4\tan A\sin A

so that

m^2-n^2=4\sqrt{mn}

as required.

5 0
3 years ago
Help plz asap !!!!!!!
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When evaluating, you must combine like terms first, so subtract 4 from 1/2 then multiply that number by -7/4, this will give you the value of x.
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