Answer:
1900
Step-by-step explanation:
1 kg = 1000g
1.2kg = x
<u>1</u><u> </u><u>kgx</u> = <u>1</u><u>2</u><u>0</u><u>0</u><u> </u><u>kg.g</u>
1kg. 1kg
x = 1200 g
1 decagram = 10g
40 decagram = x
<u>1</u><u> </u><u>dg.x</u> = <u>4</u><u>0</u><u>0</u><u> </u><u>dg.g</u>
1 dg. 1 dg
x = 400g
so the total= 1200g +300 + 400g=1900g
without the unit = 1900
Answer:
x=0
Step-by-step explanation:
substitute y=0
0= -x^2
then swap the sides
-x^2=0 ,
change the signs
x^2=0
set the base equal to 0
x=0
Answer:
t≈8.0927
Step-by-step explanation:
h(t) = -16t^2 + 128t +12
We want to find when h(t) is zero ( or when it hits the ground)
0 = -16t^2 + 128t +12
Completing the square
Subtract 12 from each side
-12 = -16t^2 + 128t
Divide each side by -16
-12/-16 = -16/-16t^2 + 128/-16t
3/4 = t^2 -8t
Take the coefficient of t and divide it by 8
-8/2 = -4
Then square it
(-4) ^2 = 16
Add 16 to each side
16+3/4 = t^2 -8t+16
64/4 + 3/4= (t-4)^2
67/4 = (t-4)^2
Take the square root of each side
±sqrt(67/4) =sqrt( (t-4)^2)
±1/2sqrt(67) = (t-4)
Add 4 to each side
4 ±1/2sqrt(67) = t
The approximate values for t are
t≈-0.092676
t≈8.0927
The first is before the rocket is launched so the only valid answer is the second one
Answer:
the answer is c, (-10,4) and the radius is 10
Step-by-step explanation:
Hope this helps!❆
69×2 [8+12-10×2+ (7-5) -1] -6
69×2 [8+12-10×2+2-1] -6
69×2 [8+12-20+2-1] -6
69×2 [20-20+2-1] -6
69×2 [0+2-1] -6
69×2 [1] -6]
138 [1] -6
138-6
132
I believe this is ur answer.
