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sukhopar [10]
3 years ago
14

Express in simplest form 2 5/6 - 1 3/10

Mathematics
1 answer:
REY [17]3 years ago
3 0

Answer:

exact form: 23/15

decimal form: 1.5333333333 (infinitely or add a little line on top of the 3)

mixed number form: 1 8/15

Step-by-step explanation:

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Help me out PLEASE. begging.
spayn [35]
The ladder will reach 122 ft up the building.

The 120 feet of the extended ladder, since it will be leaning against the building, will be the hypotenuse of the right triangle.  x will be the height from the top of the fire truck to the point where the ladder hits the building.  75° is the angle the ladder will make with the fire truck. 

We have an angle, the side opposite the angle, and the hypotenuse.  Opposite/hypotenuse is the ratio for sine, so we set up our equation as such:

x/120 = sin 75

Multiply both sides by 120:
120(x/120) = 120*sin 75
x = 120*sin 75
x ≈116

However, this is just from the top of the fire truck to the point where the ladder hits the building.  We still add the 6 feet from the top of the truck to the ground.  116+6 = 122.
5 0
3 years ago
What is 0.15 as a fraction
nydimaria [60]

Answer:

.15 of course hhsjdjdjwasting space here dont mind me

5 0
3 years ago
Read 2 more answers
For an angle Θ with the point (12, −5) on its terminating side, what is the value of cosine?
Pachacha [2.7K]
Given that the point (12,-5) which takes the form (x,y), This implies that:
opposite=-5
adjacent=12
thus using using Pythagorean theorem, the hypotenuse will be:
c^2=a^2+b^2
plugging the values we obtain:
c^2=(12)^2+(-5)^2
c^2=144+15
c^2=169
thus
c=13
but
cos θ=adjacent/ hypotenuse
therefore:
cos θ=12/13

Answer is option . D
5 0
2 years ago
Find the product. Write the product in SIMPLEST form. 4/5 x 7
Dmitry_Shevchenko [17]
The answer is 5 3/5 or in decimal form 5.6
5 0
3 years ago
Given the vector equation ????(t)=(4−3t)????+(−5+t)????+(3−t)????, rewrite this in terms of the parametric equations for the lin
Anit [1.1K]

Answer:

The parametric equations for the line.x(t)=

y(t)=

z(t)=

is  

 \= r (t) =  \left \{ {{x(t)= 4-3t} \atop {y(t)= -5+t}}  \atop {z(t)=3-t}} \right \}

Step-by-step explanation:

From the question we are told that

      the given equation is

                \= r(t) =  (4-3t) + (-5 + t) + (3-t)

This given equation can be represented as

             \= r (t) =  [4 -3t , -5+t,3-t]

Generally this equation can be represented in terms of the parametric equations as follows

   \= r (t) =  \left \{ {{x(t)= 4-3t} \atop {y(t)= -5+t}}  \atop {z(t)=3-t}} \right \}

This above equation is obtained by assigning each component of r(t) to each  line

4 0
3 years ago
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