\left[a _{3}\right] = \left[ \frac{ - b^{2}}{6}+\frac{\frac{ - b^{4}}{3}+\left( \frac{-1}{3}\,i \right) \,\sqrt{3}\,b^{4}}{2^{\frac{2}{3}}\,\sqrt[3]{\left( -1296 - 432\,b^{2} - 16\,b^{6}+\sqrt{\left( 1679616+1119744\,b^{2}+186624\,b^{4}+41472\,b^{6}+13824\,b^{8}\right) }\right) }}+\frac{\frac{ - \sqrt[3]{\left( -1296 - 432\,b^{2} - 16\,b^{6}+\sqrt{\left( 1679616+1119744\,b^{2}+186624\,b^{4}+41472\,b^{6}+13824\,b^{8}\right) }\right) }}{24}+\left( \frac{1}{24}\,i \right) \,\sqrt{3}\,\sqrt[3]{\left( -1296 - 432\,b^{2} - 16\,b^{6}+\sqrt{\left( 1679616+1119744\,b^{2}+186624\,b^{4}+41472\,b^{6}+13824\,b^{8}\right) }\right) }}{\sqrt[3]{2}}\right][a3]=⎣⎢⎢⎢⎢⎡6−b2+2323√(−1296−432b2−16b6+√(1679616+1119744b2+186624b4+41472b6+13824b8))3−b4+(3−1i)√3b4+3√224−3√(−1296−432b2−16b6+√(1679616+1119744b2+186624b4+41472b6+13824b8))+(241i)√33√(−1296−432b2−16b6+√(1679616+1119744b2+186624b4+41472b6+13824b8))⎦⎥⎥⎥⎥⎤
9/32
hope this helps
vote me brainliest
(11/12) / (2 5/8) = ...turn mixed numbers to improper fractions
(11/12) / (21/8) = ...when dividing fractions, flip what u r dividing by, then multiply
11/12 * 8/21 = 88/252 reduces to 22/63
Answer: x=3.6; y=-2.5
Step-by-step explanation:
To solve this pair of equations, we can use elimination method.
5x+4y=8
10x-4y=46
Add both equations together to cancel out 4y.
15x=54 [divide both sides by 15]
x=3.6
Now that we know x, we can plug it back into any equation to find y.
5(3.6)+4y=8 [multiply]
18+4y=8 [subtract both sides by 18]
4y=-10 [divide both sides by 4]
y=-2.5
Now, we have x=3.6 and y=-2.5.