Answer:
The correct answer is A.
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Step-by-step explanation:
Method 1
You just have to plot each point on the graph.
The one that falls within the solution region is the correct choice.
From the graph,
falls within the solution region.
See graph
Method 2
If you substitute the points into the inequalities, the only point that will satisfy both inequalities simultaneously is A.
The first inequality is
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If we substitute
, we get;
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
This statement is true.
The second inequality is

If we substitute
, we get;

This gives,
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This statement is also true.
1.) D
2.) D
3.) C
4.) C
5.) 56 and 90 I looked for the pattern and followed it.
Get someone else to do 6 I cant
Probability that the student got a 'C' GIVEN they are female = number of females that got a C in the test/number of females
From the information given,
number of females that got a C in the test = 12
number of females = 30
Thus,
Probability that the student got a 'C' GIVEN they are female = 12/30
We would simplify the fraction by dividing the numerator and denominator by 6. Thus,
Probability that the student got a 'C' GIVEN they are female = 2/5

Take both sides as powers of 4:

Do it again:
