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3 years ago

Temperature Suppose there is a 1.7°F drop in temperature for every thousand feet that an

Mathematics

1 answer:

SIZIF [17.4K]3 years ago

4 0

Answer:

wrong the answer is 63.1

Step-by-step explanation:

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Given the graph below, find the slope. <br><br> A. -3/2<br> B.3/2<br> C -2/3<br> D. 2/3

Irina18 [472]

The answer is or the slope is D 2/3

8 0

3 years ago

Anne, Bridget, and Sasha shared a sum of money. Anne took 1/3 of the total amount, and Bridget took 1/4 of the remaining money.

lesya692 [45]

Answer:

180

Step-by-step explanation:

160= 1/3 * total
160*3 = total
480 = total

bridget = 1/4(total)
bridget = 1/4(480)
bridget took 120

Sasha took 1/2 of 360
Sasha took $180.

7 0

2 years ago

Victor wants to buy fertilizer for his yard. The yard is 45 feet by 55 feet. The direction on the bag of fertilizer say that one

frosja888 [35]

Answer: 2 bags

Step-by-step explanation:

First find the area of the yard.

The area given the units would be:

= Length * Width

= 45 * 55

= ‭2,475‬ ft²

Victor needs enough fertilizer to cover ‭2,475‬ft² but each bag covers only 1,250 ft².

The number of bags needed is therefore:

= ‭2,475‬ / 1,250

= 1.98

= 2 bags

4 0

3 years ago

108/40 in its simplest form

igor_vitrenko [27]

Answer:

27/10

Step-by-step explanation:

A calculator can tell you the fraction value is 2.7. As the ratio of integers, this is ...

108/40 = 27/10

5 0

3 years ago

Find the area of the part of the plane 3x 2y z = 6 that lies in the first octant.

gavmur [86]

The area of the part of the plane 3x 2y z = 6 that lies in the first octant is mathematically given as

A=3 √(4) units ^2

<h3>What is the area of the part of the plane 3x 2y z = 6 that lies in the first octant.?</h3>

Generally, the equation for is mathematically given as

The Figure is the x-y plane triangle formed by the shading. The formula for the surface area of a z=f(x, y) surface is as follows:

$A=\iint_{R_{x y}} \sqrt{f_{x}^{2}+f_{y}^{2}+1} d x d y(1)$

The partial derivatives of a function are f x and f y.

$\begin{aligned}&Z=f(x)=6-3 x-2 y \\&=\frac{\partial f(x)}{\partial x}=-3 \\&=\frac{\partial f(y)}{\partial y}=-2\end{aligned}$

When these numbers are plugged into equation (1) and the integrals are given bounds, we get:

$&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{(-3)^{2}+(-2)^2+1dxdy} \\\\&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{14} d x d y \\\\&=\sqrt{14} \int_{0}^{2}[y]_{0}^{3-\frac{3}{2} x} d x d y \\\\&=\sqrt{14} \int_{0}^{2}\left[3-\frac{3}{2} x\right] d x \\\\$

$&=\sqrt{14}\left[3 x-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3.2-\frac{3}{2} \cdot \frac{1}{2} \cdot 3^{2}\right] \\\\&=3 \sqrt{14} \text { units }{ }^{2}$

In conclusion, the area is

A=3 √4 units ^2