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Sophie [7]
3 years ago
9

A major chemical spill occurred five years ago at Baker’s Beach, the world’s sole nesting ground for Merrick sea turtles, and pr

evented nearly all the eggs laid that year from hatching. Yet the number of adult female Merricks returning to lay their eggs at Baker’s Beach has actually increased somewhat since five years ago. Clearly, environmentalists’ prediction that the world’s Merrick population would decline as a result of the spill has proven unfounded.Which of the following, if true, most seriously undermines the argument offered in refutation of the environmentalists’ prediction?A. The chemical spill five years ago occurred at a time when there were neither Merrick sea turtles nor Merrick sea turtle eggs on Baker’s Beach.B. Female Merrick sea turtles begin returning to Baker’s Beach to lay their eggs when they are ten years old.C. Under normal conditions, only a small proportion of hatchling female Merrick sea turtles survive in the ocean until adulthood and return to lay their eggs at Baker’s Beach.D. Environmental pressures unrelated to the chemical spill have caused a significant decline in the population of one of the several species of sea birds that prey on Merrick sea turtle eggs.E. After the chemical spill, an environmental group rejected a proposal to increase the Merrick sea turtle population by transferring eggs from Baker’s Beach to nearby beaches that had not been affected by the spill.
Chemistry
1 answer:
Alja [10]3 years ago
5 0

Answer:

A) Misinformation! Contradicts info given.

B) Turtles laying eggs now were not affected by the spill. Effect of spill should be approximately 10 yrs later.

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3 years ago
Calculate the mass percentage of Na2SO4 in a solution containing 10.9 g Na2SO4 in 482 g water.
boyakko [2]

Answer:

The answer to your question is 2.21 %

Explanation:

Data

mass of Na₂SO₄ = 10.9 g

mass of H₂O       = 482 g

Formula

Percent by mass = \frac{mass of solute}{total mass} x 100

Substitution

Percent by mass = \frac{10.9}{10.9 + 482} x 100

Simplification and result

Percent by mass = \frac{10.9}{492.9} x 100

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3 0
3 years ago
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The percent yield of this reaction is consistently 92.0%. CH4(g) + 4 S(g) → CS2(g) + 2 H2S(g) How many grams of sulfur would be
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Answer:

132.17 g

Explanation:

The reaction given , in the question is -

    CH₄ (g ) + 4 S ( g ) ---> CS₂ ( g ) + 2H₂S  ( g )

From the reaction , 4 mole of S is required for the production of 1 mole of  CS₂ .

since ,

Moles of  CS₂  = given mass of CS₂ / Molecular weight  of  CS₂

Since ,

the Molecular weight of  CS₂ = 76

Given ,  mass of CS₂ =  72.57 g

Moles of  CS₂ = 72.57  / 76 = 0.95 mol

Since ,

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Moles of S required = 4 * 0.95 mol / 0.92 = 4.13 moles

Mass of S required = 4.13 * 32 = 132.17 g .

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