1) 1 molecules
2) 2 oxygen atoms
3)2 moles of Al2O3 are formed
4)4:3
The grams of aluminum that are required to produce 3.5 moles of AlO3 in presence of excess O2 is calculated as below
write the equation for reaction
4 Al + 3O2 =2 Al2O3
by use of mole ratio between Al to Al2O3 which is 4 :2 the moles of Al
=3.5 x4/2 = 7 moles
mass of Al = moles / x molar mass
= 7 moles x27 g/mol =189 grams
Answer:
The final pressure of the gas is 0.915atm
Explanation:
We have to apply the Charles Gay Lussac Law, where the pressure changes directly proportional to absolute T°
- No change in volume
- The same moles in both situations
P1 / T1 = P2 / T2
0.991 atm / 342K = P2 / 316k
(0.991 atm / 342K) . 316K = P2
0.915 atm = P2
The answer should be D) electrical