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Elanso [62]
2 years ago
14

Example of each class of polydentate ligands

Chemistry
1 answer:
Elena-2011 [213]2 years ago
5 0

Answer:

EDTA, a hexadentate ligand

Explanation:

pls mark me as brainly

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For the purpose of proper representation in this item, we let the number of moles of carbon in the compound be x, that of H is y. The equation of toluene now becomes,
                   CxHy
The combustion reaction is,
        CxHy + O2 --> CO2 + H2O

The equation presented above may not be balanced yet. Then, we determine the number of mmols of C, H, and O in the product using the given masses.
    
(1) 8.20 mg CO2
             (8.2 mg CO2)(1 mmol CO2/44 mg CO2) = 0.186 mmol CO2
     which means,
                     0.186 mmol C
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(2) 1.92 mg H2O
            (1.92 mg H2O)(1 mmol H2O/18 mg H2O) = 0.107 mmol H2O
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                    0.2133 mmol H
                    0.107 mmol O

Thus, the equation for toluene is,
               C(0.186)H(0.2133)

Dividing the numbers by the lesser value,
               CH(8/7)
To eliminate the fraction, we multiply by the denominator. Thus, the final answer would be,
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