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Tems11 [23]
3 years ago
7

HCN(aq)+SO4-2(aq)HSO4-(aq)+CN-(aq)

Chemistry
1 answer:
Elina [12.6K]3 years ago
8 0
<span>HCN(aq)+SO4-2(aq)HSO4-(aq)+CN-(aq)
</span>
Bronsted-Lowry acid in this equation:<span>
Bronsted lowry acid=HCN(aq)

</span>Bronsted-Lowry Base in this equation:<span>
Bronstes lowry base =SO4-2

</span>Conjugate acid in this equation:
CA=CN-<span>

</span>Conjugate base in this equation
CB=HSO4- <span>

</span>
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The part of the atom that is free to move between materials is???
Kruka [31]

Answer:

Electrons

Explanation:

4 0
2 years ago
Specify the number of protons, neutrons, and electrons in the neutral atom bromine-80.
jolli1 [7]
  80 equals the mass number. In the periodic table, the atomic number of Bromine is 35. The atomic number equals the number of protons.
  80-35= number of neutrons (mass-protons)
So, we have P=35   N=45
Furthermore, since the atom is neutral that must mean that the number of electrons equals the number of protons.
e=35
5 0
3 years ago
A 0.100 m solution of a monoprotic weak acid has a ph of 3.00. what is the pka of this acid?
Lelechka [254]
Answer is: pKa for the monoprotic acid is 5.<span>
Chemical reaction: HA(aq) </span>⇄ A⁻(aq) + H⁺<span>(aq).
c(monoprotic acid) = 0.100 M.
pH = 3.00.
[A</span>⁻] = [H⁺] = 10∧(-3).<span>
[A</span>⁻] = [H⁺] = 0.001 M; equilibrium concentration.<span>
[HA] = 0.1 M - 0.001 M.
[HA] = 0.099 M.
Ka = [A</span>⁻]·[H⁺] / [HA].<span> 
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Ka = 0.00001 M = 1.0·10</span>⁻⁵ M.
<span>pKa = -logKa = 4.99.

</span>
7 0
3 years ago
Read 2 more answers
Why would putting argon and pottassium in order of there atomic masses be wrong
coldgirl [10]
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8 0
3 years ago
A 15.5 g piece of chromium, heated to 100.0 degrees Celsius, is dropped into 55.5 g of water at 16.5 degrees Celsius. The final
elixir [45]

Answer: The specific heat capacity of chromium is 2010J/g^0C

Explanation:

heat_{absorbed}=heat_{released}

As we know that,  

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]         .................(1)

where,

q = heat absorbed or released

m_1 = mass of chromium = 15.5 g

m_2 = mass of water = 55.5 g

T_{final} = final temperature =18.9^0C

T_1 = temperature of chromium = 100^oC

T_2 = temperature of water = 16.50^oC

c_1 = specific heat of chromium= ?

c_2 = specific heat of water= 4.184J/g^0C

Now put all the given values in equation (1), we get

-15.5\times c_1\times (19.5-18.9)=[55.5\times 4.184\times (19.5-100)]

c_1=2010J/g^0C

The specific heat capacity of chromium is 2010J/g^0C

6 0
3 years ago
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