3 years ago

Plants are able to produce special chemicals at the right time and place.

Chemistry

2 answers:

Alisiya [41]3 years ago

6 0

Hi There,

The answer is:

True

Hope this helps have a great day :)

Luden [163]3 years ago

4 0

TRUE its glucose if they have sunlight

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Calculate the molar solubility of silver(i) bromate with ksp = 5. 5×10-5. also, convert the molar solubility to the solubility.

Sindrei [870]

The molar solubility is 7.4× $10^{-3}$ M and the solubility is 7.4× $10^{-3}$ g/L .

Calculation ,

The dissociation of silver bromide is given as ,

$AgBr$ → $Ag ^{+}$ + $Br^{-}$

- S S

Ksp = [ $Ag ^{+}$ ] [ $Br^{-}$ ] = [S] [ S ] = $S^{2}$

S = √ Ksp = √ 5. 5× $10^{-5}$ = 7.4× $10^{-3}$

The solubility =7.4× $10^{-3}$ g/L

The molar solubility is the solubility of one mole of the substance.

Since , one mole of $AgBr$ is dissociates and form one mole of each $Ag ^{+}$ and $Br^{-}$ ion . So, solubility is equal to molar solubility but unit is different.

Molar solubility = 7.4× $10^{-3}$ mol/L = 7.4× $10^{-3}$ M

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