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krok68 [10]
3 years ago
12

Either a single number, variable, or numbers and/ or variable multipled together is a called

Mathematics
1 answer:
adoni [48]3 years ago
3 0
A term




Hope this helps!
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Picture of problem below NO LINKS
iragen [17]

Answer:

600$

Step-by-step explanation:

I think this is right

5 0
3 years ago
Solve for x and y:<br> 3/x -1/y =13/10<br> 1/x + 2/y =9/10
harkovskaia [24]

Answer:

  (x, y) = (2, 5)

Step-by-step explanation:

I find it easier to solve equations like this by solving for x' = 1/x and y' = 1/y. The equations then become ...

  3x' -y' = 13/10

  x' +2y' = 9/10

Adding twice the first equation to the second, we get ...

  2(3x' -y') +(x' +2y') = 2(13/10) +(9/10)

  7x' = 35/10 . . . . . . simplify

  x' = 5/10 = 1/2 . . . . divide by 7

Using the first equation to find y', we have ...

  y' = 3x' -13/10 = 3(5/10) -13/10 = 2/10 = 1/5

So, the solution is ...

  x = 1/x' = 1/(1/2) = 2

  y = 1/y' = 1/(1/5) = 5

  (x, y) = (2, 5)

_____

The attached graph shows the original equations. There are two points of intersection of the curves, one at (0, 0). Of course, both equations are undefined at that point, so each graph will have a "hole" there.

3 0
3 years ago
What is 5(34)68+76 can u guys give me the answer I really need help
Ratling [72]
5x34= 170
68+76= 144
170+144= 314
4 0
3 years ago
Read 2 more answers
A pilot flew a 400 mile flight in 2.5 hours flying into the wind. Flying the same rate and with the same wind speed the return t
eduard

Answer: 20 mph

Explanation:

Speed is a physical quantity which is equal to the ratio between the distance covered (d) and the time taken (t):

v=\frac{d}{t}

In the first part of the problem, the plane flew a distance of d=400 mi in a time of t=2.5 h. The speed of the plane in this case was the difference between the proper speed of the plane, v, and the speed of the wind, w, since the plane flew opposite to the wind. So we can write:

v-w=\frac{400mi}{2.5h}=160 mph (1)

During the return trip, the plane flew with a speed (v+w), since the wind was on the tail, and it took 2 hours to cover the same distance:

v+w=\frac{400 mi}{2 h}=200 mph (2)

So we have two equations with two unknown variables. From (1), we get

v=160+w

Substituting into eq.(2)

(160+w)+w=200\\160+2w=200\\2w=40\\w=20 mph

So, the speed of the wind was 20 mph.

3 0
3 years ago
Read 2 more answers
Please help with math
bezimeni [28]

Answer:

First, third, and fourth one would be the answers.

4 0
3 years ago
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