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2 years ago

In which of the following ways linear system similar to quadratic systems? Select all that apply

Mathematics

2 answers:

Finger [1]2 years ago

4 0

1.

Answer:

A. Both can be solved by graphing.

C. Both can be solved by substitution.

D. Both have solutions at the points of intersection.

Step-by-step explanation:

Linear systems and quadratic systems both are solved by graphing and substitution.

We can graph both the systems. In linear systems , we get lines and in quadratic systems we get curves .

The points of intersection of two lines or curves are the solutions of the respectively system.

We can substitute the value of one variable in the equation find the solution.

2.

The correct answers are:

A) Both can be solved by graphing;

C) Both can be solved by substitution; and

D) Both have solutions at the points of intersection.

Explanation:

Just as a system of linear equations can be solved by graphing, a system of quadratic equations can as well. We graph both equations. We then look for the intersection points of the graphs; these intersection points will be the solutions to the system.

We can also solve the system by substitution. If we can get one variable isolated, we can substitute this into the other equation to solve.

3.

Answers:

Both can be solved by graphing.

Both can be solved by substitution.

Both have solutions at the points of intersection.

Step-by-step explanations:

I put those answers on my test and got then correct.

Jobisdone [24]2 years ago

3 0

. Both can be solved by graphing. Both can have two solutions.

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AlladinOne [14]

Answer:

$4-2.326\frac{1}{\sqrt{100}}=3.767$

$4+2.326\frac{1}{\sqrt{100}}=4.233$

So on this case the 98% confidence interval would be given by (3.767;4.233)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

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$\mu$ population mean (variable of interest)

$\sigma=1$ represent the population standard deviation

n=100 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.98 or 98%, the value of $\alpha=0.02$ and $\alpha/2 =0.01$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.01,0,1)".And we see that $z_{\alpha/2}=2.326$

Now we have everything in order to replace into formula (1):

$4-2.326\frac{1}{\sqrt{100}}=3.767$

$4+2.326\frac{1}{\sqrt{100}}=4.233$

So on this case the 98% confidence interval would be given by (3.767;4.233)

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