Answer:
Step-by-step explanation:
Given the coordinate points (6, -3) and (7, -10), we are to find the equation of a line passing through this two points;
The standard equation of a line is y = mx+c
m is the slope
c is the intercept
Get the slope;
m = Δy/Δx = y2-y1/x2-x1
m = -10-(-3)/7-6
m = -10+3/1
m = -7
Get the intercept;
Substitute the point (6, -3) and m = -7 into the expression y = mx+c
-3 = -7(6)+c
-3 = -42 + c
c = -3 + 42
c = 39
Get the required equation by substituting m = -7 and c= 39 into the equation y = mx+c
y = -7x + 39
Hence the required equation is y = -7x + 39
D) a numerical expressions
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V = (1/3) x πr² x h = cm³
Answer:
B
Step-by-step explanation:
Answer:
maximum value of y = 3
Step-by-step explanation:
line Starts at -4 , 0 & turns at - 1 , 3
Slope = (3 - 0)/(-1 -(-4)) = 3/3 = 1
y = x + c
=> 0 = - 4 + c => c = 4
=> y = x + 4
line after turning crosses the y-axis at (0, 2) and the x-axis at (2, 0)
slope of this line : (0-2)/(2-0) = -1
y = - x + c
2 = 0 + c => c = 2
=> y = - x + 2
=> y = 2 - x
Values Drawn
x y
-4 0
-3 1
-2 2
-1 3
0 2
1 1
2 0