Answer:
B) -4
Step-by-step explanation:
m= (0 - (-4)) / (2 - 0) = 4 / 2 = 2
f(2) = 2 * 2 + b = 0
f(0) = 2 * 0 + b = -4
b = -4
Answer:
2.80
Step-by-step explanation:
The discount is the regular price times the discount
discount = 19 *15%
discount = 2.85
The new price is the regular price minus the discount
new price = 19-2.85
=16.15
Now she has to pay the sales tax
tax = new price * tax rate
tax= 16.15 * 6.5%
= 16.15 *.065
=1.05
We add the tax to the new price to get the final price
final price = new price+tax
= 16.15 +1.05
=17.20
She pays with a 20 dollar bill
Change = payment - final price
=20.00 - 17.20
= 2.80
Answer:
See the proof below.
Step-by-step explanation:
Assuming this complete question: "For each given p, let Z have a binomial distribution with parameters p and N. Suppose that N is itself binomially distributed with parameters q and M. Formulate Z as a random sum and show that Z has a binomial distribution with parameters pq and M."
Solution to the problem
For this case we can assume that we have N independent variables
with the following distribution:
bernoulli on this case with probability of success p, and all the N variables are independent distributed. We can define the random variable Z like this:
From the info given we know that
We need to proof that
by the definition of binomial random variable then we need to show that:


The deduction is based on the definition of independent random variables, we can do this:

And for the variance of Z we can do this:
![Var(Z)_ = E(N) Var(X) + Var (N) [E(X)]^2](https://tex.z-dn.net/?f=%20Var%28Z%29_%20%3D%20E%28N%29%20Var%28X%29%20%2B%20Var%20%28N%29%20%5BE%28X%29%5D%5E2%20)
![Var(Z) =Mpq [p(1-p)] + Mq(1-q) p^2](https://tex.z-dn.net/?f=%20Var%28Z%29%20%3DMpq%20%5Bp%281-p%29%5D%20%2B%20Mq%281-q%29%20p%5E2)
And if we take common factor
we got:
![Var(Z) =Mpq [(1-p) + (1-q)p]= Mpq[1-p +p-pq]= Mpq[1-pq]](https://tex.z-dn.net/?f=%20Var%28Z%29%20%3DMpq%20%5B%281-p%29%20%2B%20%281-q%29p%5D%3D%20Mpq%5B1-p%20%2Bp-pq%5D%3D%20Mpq%5B1-pq%5D)
And as we can see then we can conclude that 
Answer:Mai has picked 1 cup of strawberries for a cake which is enough for 3/4 of the cake. How many cups does she need for the whole cake?
Step-by-step explanation:
If f(x) = 0 then it is a root
x + 3 = 0
x=-3
f(-3) = (-3)^4 + 10(-3)^3 + 23(-3)^2 - 34(-3) - 120 = 0
x - 2 = 0
x=2
f(2) = (2)^4 + 10(2)^3 + 23(2)^2 - 34(2) - 120 = 0