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allochka39001 [22]
3 years ago
8

Trapezoid E F G H is reflected across line of reflection k to form trapezoid E prime F prime G prime H prime. Trapezoid E prime

F prime G prime H prime is shifted down to E double-prime F double-prime G double-prime H double-prime.
Which composition of transformations maps figure EFGH to figure E"F"G"H"?

a reflection across line k followed by a translation down
a translation down followed by a reflection across line k
a 180° rotation about point G followed by a translation to the right
a translation to the right followed by a 180° rotation about point G
Mathematics
2 answers:
Aleks [24]3 years ago
8 0

Answer:

Its A

Step-by-step explanation:

i just took the quiz and got it right

andrezito [222]3 years ago
3 0

Answer:

A a reflection across line k followed by a translation down

Step-by-step explanation:

EDGE 2020

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Can anyone help me? My teacher just recently taught me this today, be he never explained much. The question is in the photo
IceJOKER [234]

You've got five different problems in this photo ... four on top and the word problem on the bottom ... and they're all exactly the same thing:  Taking two points and finding the slope of the line that goes through them.

In every case, the procedure is the same.
If the two points are  (x₁ , y₁)  and  (x₂ , y₂) , then
the slope of the line that goes through them is

                          Slope  =  (y₂ - y₁) / (x₂ - x₁) .

This is important, and you should memorize it.

#1).  (8, 10)  and  (-7, 14)

         Slope  =  (14 - 10) / (-7 - 8)  =  4 / -15

#2).  (-3, 1)  and  (-17, 2)

         Slope  =  (2 - 1) / (-17 -  -3)  =  (2 - 1) / (-17 + 3)  =  1 / -14

#3).  (-20, -4)  and  (-12, -10)

         Slope  =  [ -10 - (-4) ] / [ -12 - (-20) ]

=========================================

The word problem:

This question only gives you one point on the graph,
and then it wants to know what's the slope ?
What are you going to do for another point ?

A "proportional relationship" always passes through the origin,
so another point on the line is  (0, 0) .

Now you have two points on THAT line too, and you can easily
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4 0
3 years ago
Can someone help me with questions 2 and 3 pls?
bija089 [108]

1 cup = 1/2 pint, so where it says 4 cups we'll just read 2 pints.

1.  In one show we serve 30 × 2 pints of small and 42 × 6 pints of regular.

Total = 30 × 2 + 42 × 6 =  60 + 252 = 312 pints

Answer: 312 pints

2. 8 pints per gallon, 2 gallons per container makes 16 pints per container.  

312 pints / 16 pints per container = 19.5 containers

We round up since we need a whole number of containers.

Answer: 20 containers

We can't really see question 3.

7 0
3 years ago
Find a power series representation for the function. (Assume a>0. Give your power series representation centered at x=0 .)
melamori03 [73]

Answer:

Step-by-step explanation:

Given that:

f_x = \dfrac{x^2}{a^7-x^7}

= \dfrac{x^2}{a^7(1-\dfrac{x^7}{a^7})}

= \dfrac{x^2}{a^7}\Big(1-\dfrac{x^7}{a^7} \Big)^{-1}

since  \Big((1-x)^{-1}= 1+x+x^2+x^3+...=\sum \limits ^{\infty}_{n=0}x^n\Big)

Then, it implies that:

\implies  \dfrac{x^2}{a^7} \sum \limits ^{\infty}_{n=0} \Big(\Big(\dfrac{x}{a} \Big)^{^7} \Big)^n

= \dfrac{x^2}{a^7} \sum \limits ^{\infty}_{n=0} \Big(\dfrac{x}{a} \Big)^{^{7n}}

= \dfrac{x^2}{a^7} \sum \limits ^{\infty}_{n=0} \Big(\dfrac{x^{7n}}{a^{7n}} \Big)}

\mathbf{=  \sum \limits ^{\infty}_{n=0} \dfrac{x^{7n+2}}{a^{7n+7}} }}

7 0
3 years ago
The perimeter of a square is 24 4/9 in, and its side is 6 1/9 in. Find its area.
ra1l [238]
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7 0
3 years ago
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Sonja [21]

Answer:

D

Step-by-step explanation:

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x^3 is also x^2 * x and since x^2 has a perfect square root which is just x that goes outside while the remaining x stays inside.

y^9 is also y^8 * y and since we move variables out the radical in twos y^ goes outside the radical and y stays inside alone.

Finally, z is just z it can't be taken out so it stays inside the radical.

Hope that helps!

8 0
3 years ago
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