Me I am very good at math I am a tutor
Answer:
Helen’s net is correct because she reorganized the solid as a triangular prism.
This is because the net has a rectangular base and 4 triangular sides.
Step-by-step explanation:
Rectangular SA one side+1 = 30 x 9 = 270 + 1s= 270 x 2 =540sq^2
Rectangular side one side +1 = 18 x 9 = 162 +1s = 162 x 2 = 324sq^2
2 x 2 triangular sides either end = 4/3 x 15 x 27.3 + 18 x 30.9 = 409.5 (x2) = 819sq^2
=864 + 360
Pyramid area = 1236.71sq^2
Volume = V=1620^3
Answer:
y = -2x + 25
Step-by-step explanation:
A standard equation can be in slope-intercept form: y = mx + b
m is the slope, b is the y-intercept.
Plug in the given slope.
y = -2x + b
To find b, plug in the given point (9, 7).
7 = -2(9) + b
Multiply.
7 = -18 + b
Add 18 to both sides to find b.
25 = b
Plug this into your standard equation.
y = -2x + 25
Check by plugging in the given point again.
7 = -2(9) + 25
7 = -18 + 25
7 = 7
Your answer is correct!
Hope this helps!
Answer:
138, 460 m²
Step-by-step explanation:
How To Find Volume of Pyramid With Slant Height? If 'x' is the base length, 's' is the slant height, and 'h' is the height of a regular pyramid, then they satisfy the equation (the Pythagoras theorem) (x/2)2 + h2 = s2.