Answer:
The sum of the first 37 terms of the arithmetic sequence is 2997.
Step-by-step explanation:
Arithmetic sequence concepts:
The general rule of an arithmetic sequence is the following:

In which d is the common diference between each term.
We can expand the general equation to find the nth term from the first, by the following equation:

The sum of the first n terms of an arithmetic sequence is given by:

In this question:

We want the sum of the first 37 terms, so we have to find 




Then

The sum of the first 37 terms of the arithmetic sequence is 2997.
What is the question that you are asking? Do you need to write an equation?
Answer:
PR= 8
ST=5
Step-by-step explanation:
PQ and PR are congruent so
2x=8
x=4
2*4=8
PR=8
ST and TU are congruent so
5z=2z+3
3z=3
z=1
5*1=5
ST=5
Area of a rectangle=length×width. If the area is 161 and the length is 14 then that means: 161=14×width. You would then divide 161÷14 and you will find that the width is 11.5.
Step-by-step explanation:
Given,
Base of the triangle

Hypotenuse of the triangle = 5
Height of the triangle = x
Therefore, According to Pythagoras Theorem,







Hence, the required value of <u>x is 1.</u>