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3 years ago

In ∆PQR, ∠P = 90degrees , PQ= 12 cm, PR=16cm. Find ∠Q

Mathematics

1 answer:

siniylev [52]3 years ago

5 0

Answer:

∠Q = 53.13 degrees

Step-by-step explanation:

Given that ∆PQR, ∠P = 90degrees , this means that the triangle is a right angled triangle

Hence using the notation

SOH CAH TOA

where S is sine, C is cosine, T is tangent and O, A and H represents the size of the opposite, adjacent and hypotenuse sides

Considering ∠Q and the given sides

PR=16cm is the opposite side,

PQ= 12 cm is the adjacent side hence we use TOA

Tan Q = 16/12 =

Q = Arc tan 16/12

= 53.13 degrees

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3 years ago

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kirza4 [7]

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3 years ago

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julia-pushkina [17]

Given:

12cm to 2.5mm

To find:

The simplified for of given statement.

Solution:

We know that,

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It can be written as

$\dfrac{12\ cm}{2.5\ mm}=\dfrac{120\ mm}{2.5 mm}$

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