Answer:
CH₄ will diffuse at faster rate.
Explanation:
According to Graham's law,
The rate of diffusion is inversely proportional to the square root of molar mas of gas.
It is given in question the molar mass of CH₄ is 16 g. Thus the square rot of 16 is.
√16 = 4
The molar mass of SO₂ is 64 g and the square root is,
√64 = 16
As it is stated that diffusion rate is inversely related to the square root of molar mass thus the diffusion rate of SO₂ is lower while methane diffuse faster.
I can't remember any of the weights of the individual elements but here is how you solve it:
Molecular weight of copper + nitrogen + 3 oxygens = molecular weight of the compound.
M = moles / liter
.350 moles / 1 liter
Do .350 moles / liter x the molecular weight (g / mole) of the compound = the answer in g / L
Answer:
a) 6.3 cm
b) 8.0 cm
c) 0.7875
Explanation:
(a) The compound has moved above upto 7.3 cm from the bottom of the paper. Let us assume that line is drawn at 1.0 cm mark as the origin of spot. \
Distance traversed by compound= 7.3 - 1.0 cm = 6.3 cm
(b) Distance traversed by the solvent = 9.0 - 1.0 cm = 8.0 cm
(c) The Rf = Compound Migration distance / Solvent front migration distance
= 6.3/8.0 = 0.7875
Answer:
3) ester
Explanation:
Esterification is the process in which alkanol and alkanoic acids reacts in the presence of a catalyst and heat. The product is usually an ester(alkanoate) and water.
For the reaction between ethanoic acid and 1-butanol, the product is butylethanoate and water as shown below:
CH₃COOH + C₄H₈OH → CH₃COOC₄H₈ + H₂O
Answer:
C
Explanation:
The ions are first accelerated electrically, and then bended magnetically to sort them and record them.
