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3 years ago

pleeeaaaseeeee answer asappppppppp!!!!!!!!!!! Explain the processes of evaporation and condensation using the image above

Chemistry

2 answers:

goldfiish [28.3K]3 years ago

5 0

In the lake that the rivers lead, water molecules evaporate into the sky and form clouds. In the sky, these water droplets condense and form clouds that will eventually rain.

stepan [7]3 years ago

3 0

The water evaporates and then, the clouds form condensation, because the gas becomes water, and falls as rain.

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Is a oak tree a invertebrates

viva [34]

Answer:

yes

Explanation:

oak trees don't have vertebrates

7 0

3 years ago

Read 2 more answers

1. Determinati masa moleculara, raportul atomic si raportul de masa pentru oxidul de aluminiu 2. Determinati compozutia procebtu

elena-14-01-66 [18.8K]

Answer:

im solving now

Explanation:

4 0

3 years ago

Silver chloride, AgCl (Ksp = 1.8 x 10‒10), can be dissolved in solutions containing ammonia due to the formation of the soluble

Sergeeva-Olga [200]

Explanation:

The given reaction will be as follows.

$AgCl(s) \rightarrow Ag^{+}(aq) + Cl^{-}(aq)$ ............. (1)

$K_{sp}$ = $[Ag^{+}][Cl^{-}] = 1.8 \times 10^{-10}$

Reaction for the complex formation is as follows.

$Ag^{+}(aq) + 2NH_{3}(aq) \rightleftharpoons [Ag(NH_{3})_{2}]^{+}(aq)$ ........... (2)

$K_{f}$ = $\frac{[Ag(NH_{3})_{2}]}{[Ag^{+}][NH_{3}]^{2}} = 1.0 \times 10^{8}$

When we add both equations (1) and (2) then the resultant equation is as follows.

$AgCl(s) + 2NH_{3}(aq) \rightarrow [Ag(NH_{3})_{2}]^{+}(aq) + Cl^{-}(aq)$ ............. (3)

Therefore, equilibrium constant will be as follows.

K = $K_{f} \times K_{sp}$

= $1.0 \times 10^{8} \times 1.8 \times 10^{-10}$

= $1.8 \times 10^{-2}$

Since, we need 0.010 mol of AgCl to be soluble in 1 liter of solution after after addition of $NH_{3}$ for complexation. This means we have to set

$[Ag^{+}]$ = $[Cl^{-}]$

= $\frac{0.010 mol}{1 L}$

= 0.010 M

For the net reaction, $AgCl(s) + 2NH_{3}(aq) \rightarrow [Ag(NH_{3})_{2}]^{+}(aq) + Cl^{-}(aq)$

Initial : 0.010 x 0 0

Change : -0.010 -0.020 +0.010 +0.010

Equilibrium : 0 x - 0.020 0.010 0.010

Hence, the equilibrium constant expression for this is as follows.

K = $\frac{[Ag(NH_{3})^{+}_{2}][Cl^{-}]}{[NH_{3}]^{2}}$

$1.8 \times 10^{-2}$ = $\frac{0.010 \times 0.010}{(x - 0.020)^{2}}$

x = 0.0945 mol

or, x = 0.095 mol (approx)

Thus, we can conclude that the number of moles of $NH_{3}$ needed to be added is 0.095 mol.

3 0

4 years ago

What is the molarity of a 17.0% by mass solution of sodium acetate, NaC2H3O2 (82.0 g/mol), in water? The density of the solution

sattari [20]

Answer:

[NaCH₃COO] = 2.26M

Explanation:

17% by mass is a sort of concentration. Gives the information about grams of solute in 100 g of solution. (In this case, 17 g of NaCH₃COO)

Let's determine the volume of solution, by density

Mass of solution / Volume of solution = Solution density

100 g / Volume of solution = 1.09 g/mL

100 g / 1.09 g/mL = 91.7 mL

17 grams of solute is contained in 91.7 mL

Molarity (M) = Mol of solute /L of solution

91.7 mL / 1000 = 0.0917L

17 g / 82 g/m = 0.207 moles

Molariy = 0.207 moles / 0.0917L → 2.26M

4 0

3 years ago

Predict which substance has greater molar entropy. Explain.(c) Na(s) or K(s)

tigry1 [53]

K (Potassium) has higher molar entropy than sodium.

The substance's condition has the most impact on the molar entropy. Compounds that are gases will have a far higher molar entropy than compounds that are liquids or solids because gases are much more widely dispersed. A substance's entropy rises as its molecular weight, complexity, and temperature rise. As the pressure or concentration decreases, the entropy likewise rises. Gas entropies are significantly higher than those of condensed phases. The highest entropy is in gases. This is due to the wide variety of microstates in which gases can reside. The amount of freedom that atoms in a substance have to disperse, migrate, and organize themselves randomly is referred to as entropy.

Learn more about molar entropy here-

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6 0

1 year ago