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Tcecarenko [31]

3 years ago

5

Sam and Bruno were computing how many kilometers they rode in the 3 bike trips they took last month. In order, they rode 45.7, 4

0.9, and 38 miles. Their solutions are shown.

1 answer:

Eddi Din [679]3 years ago

4 0

Answer:

We are given number of miles the 3 bike trips they took last month = 45.7, 40.9, and 38 miles.

Sam and Bruno were computing how many kilometers.

Also one kilometer equals 0.621 miles.

From this we can see than 1 kilometer is smaller unit and a mile is a larger unit.

In order to convert number of miles into kilometers, we need to divide each number of mile by 0.621 miles.

We always divide a larger value by a smaller value to get the smaller unit.

Therefore,

Bruno is correct. When going from a larger unit to a smaller unit you need to divide.

Step-by-step explanation:

Hopefully this helped, if not HMU and I will get u a better answer.

<em>-Have a great day! :)</em>

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See explanation

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All the sides of the rhombus are congruent: $|DG|\cong |GF| \cong |EF| \cong |DE|$
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Using the distance formula; $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

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$\implies |EF|=\sqrt{a^2+b^2+c^2+2ab}$

$|DE|=\sqrt{(0-(-a-b))^2+(2c-c)^2}$

$\implies |DE|=\sqrt{a^2+b^2+c^2+2ab}$

Using the slope formula; $m=\frac{y_2-y_1}{x_2-x_1}$

The slope of EG is $m_{EG}=\frac{2c-0}{0-0}$

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The slope of EG is undefined hence it is a vertical line.

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The slope of DF is zero, hence it is a horizontal line.

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Conclusion:

Since $|DG|\cong |GF| \cong |EF| \cong |DE|$ and $DF \perp FG$ , DEFG is a rhombus

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