Answer:
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Step-by-step explanation:
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hope it helps
Answer:
x=11, y=2
Step-by-step explanation:
We can set 1 equal to x-5y and then solve for x. and y.
x = 5y+1
y = x-1/5
We can use this information and plug back in the values for 3y-x or x-5y.
We can set -3 = 3y-x or 1 = x-5y.
To solve for x using -3 = 3y-x we can swap the values of x and y which would make it -3 = 3(x-1/5)-5(x-1/5)+1.
We can do a bit of algebra which would get us x = 11.
Knowing that y = x-1/5 we can plug in 11 for x. y = 11-1/5.
y=2
x=11, y=2
Answer:
No they are not equal
Step-by-step explanation:
Answer:
x = 35
Step-by-step explanation:
Since m1=m2 :

Hey there! :)
Answer:
Third option. x = 2, and x = 4.
Step-by-step explanation:
Find the zeros of this quadratic equation by factoring:
f(x) = x² - 6x + 8
Becomes:
f(x) = (x - 4)(x - 2)
Set each factor equal to 0 to solve for the roots;
x - 4 = 0
x = 4
x - 2 = 0
x = 2
Therefore, the zeros of this equation are at x = 2, and x = 4.