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fomenos
3 years ago
11

What is the prominent part of animal tissue:

Biology
1 answer:
BARSIC [14]3 years ago
4 0
<span>That would be lipids or fat molecules. It is one of the four biomolecules including proteins, carbohydrates, and nucleotides.
</span>
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How does extracellular glucose inhibit transcription of the lac operon?
Genrish500 [490]

The extracellular glucose inhibit transcription of the lac operon (D) by reducing the levels of intracellular cAMP.

Lac operon is the assembly of various genes that are involved in the uptake and metabolism of lactose of E. coli or any other bacteria. It consists of a regulator gene, promoter gene, operator and structural gene. Structural genes are three: z, y and a. Each codes for a different enzyme.

cAMP is the cyclic Adenosine Monophosphate. It is produced by the bacteria when there are low levels of glucose in it. Hence it is also named as hunger signals. Therefore, cAMP is responsible for activating the operon to produce lactose.

To know more about cAMP, here

brainly.com/question/13794408

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3 0
2 years ago
What might be a reason a soldier with an amputated arm might experience phantom limb pain?
alexdok [17]
"The body develops proprioceptors to compensate for the missing limb" is the one among the following choices that <span>might be a reason a soldier with an amputated arm might experience phantom limb pain. The correct option among all the options that are given in the question is the fourth option or option "d".</span>
8 0
3 years ago
Transformed bacteria are plated on LB plus ampicillin to determine which cells were successfully transformed. Which part of the
mina [271]

Answer:

The gene that encodes ampicillin resistance.

Explanation:

The plasmid would contain the ampicillin resistance gene which gets expressed in the presence of ampicillin.

5 0
2 years ago
Plaque formation in virus is done for :
mr_godi [17]

Answer:

I think the answer is determining infectivity of a virus

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hope that it will help you

6 0
3 years ago
Transcribe the following DNA sequence to make mRNA molecule <br><br>GGAATGAGAATTC
GenaCL600 [577]
CCUUACUCUUAAG is the mRNA sequence
5 0
3 years ago
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