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2 years ago

BRAINLIEST Look at the pattern and decide what number comes next. 2 7 3 8 4 9 5 ?

Mathematics

2 answers:

baherus [9]2 years ago

4 0

Answer:

Step-by-step explanation:

2 + 5 = 7

3 + 5 = 8

4 + 5 = 9

5 + 5 = 10

brilliants [131]2 years ago

3 0

Answer:

mo bamba

Step-by-step explanation:

sicko mode

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Is 1.75 less or greater than 1 1/2

julsineya [31]

Answer:

Greater 1 1/2 is 1.50

Step-by-step explanation:

Please Brainliest if right <3

7 0

2 years ago

Read 2 more answers

HELP ILL GIVE BRAINLIEST

SVETLANKA909090 [29]

Answer:

$\huge\boxed{\bf\:c = \frac{11}{4}}$

Step-by-step explanation:

$4c + 2c = 4c + \frac{11}{2}$

Cancel 4c on both the sides of the equation.

$2c = \frac{11}{2}$

Bring the 2 in the denominator of 11/2 to the left hand side of the equation.

$2*2c = 11\\4c = 11$

Bring 4 to the right hand side if the equation.

$\boxed{\bf\:c = \frac{11}{4}}$

$\rule{150pt}{2pt}$

4 0

1 year ago

Write each mixed as a decimal.<br> a) 1 3/4<br> b) 2 13/20

kakasveta [241]

Answer:

a. 1.75

b. 2.65

those are as a decimal

6 0

2 years ago

Use mathematical induction to prove the statement is true for all positive integers n, or show why it is false:

kondaur [170]

$\text{Proof by induction:}$
$\text{Test that the statement holds or n = 1}$

$LHS = (3 - 2)^{2} = 1$
$RHS = \frac{6 - 4}{2} = \frac{2}{2} = 1 = LHS$
$\text{Thus, the statement holds for the base case.}$

$\text{Assume the statement holds for some arbitrary term, n= k}$
$1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2} = \frac{k(6k^{2} - 3k - 1)}{2}$

$\text{Prove it is true for n = k + 1}$
$RTP: 1^{2} + 4^{2} + 7^{2} + ... + [3(k + 1) - 2]^{2} = \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2} = \frac{(k + 1)[6k^{2} + 9k + 2]}{2}$

$LHS = \underbrace{1^{2} + 4^{2} + 7^{2} + ... + (3k - 2)^{2}}_{\frac{k(6k^{2} - 3k - 1)}{2}} + [3(k + 1) - 2]^{2}$
$= \frac{k(6k^{2} - 3k - 1)}{2} + [3(k + 1) - 2]^{2}$
$= \frac{k(6k^{2} - 3k - 1) + 2[3(k + 1) - 2]^{2}}{2}$
$= \frac{k(6k^{2} - 3k - 1) + 2(3k + 1)^{2}}{2}$
$= \frac{k(6k^{2} - 3k - 1) + 18k^{2} + 12k + 2}{2}$
$= \frac{k(6k^{2} - 3k - 1 + 18k + 12) + 2}{2}$
$= \frac{k(6k^{2} + 15k + 11) + 2}{}$
$= \frac{(k + 1)[6k^{2} + 9k + 2]}{2}$
$= \frac{(k + 1)[6(k + 1)^{2} - 3(k + 1) - 1]}{2}$
$= RHS$

Since it is true for n = 1, n = k, and n = k + 1, by the principles of mathematical induction, it is true for all positive values of n.

3 0

3 years ago

Estimate : 1) 48% of 8 2) 3% of 119 3) 26% of 32 4) 76% of 280

zaharov [31]

1) 48% of 8=3.84
2) 3% of 119=3.57
3) 26% of 32=8.32
4) <span>76% of 280=212.8

Hope this helps ya!</span>

7 0

2 years ago