Answer:x=10/3
Step-by-step explanation:
Use the distance formula:
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![\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}](https://tex.z-dn.net/?f=%20%5Csqrt%7B%28x_2%20-%20x_1%29%5E2%20%2B%20%28y_2%20-%20y_1%29%5E2%7D)
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Plug in the given coordinates:
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![\sqrt{(-3-1)^2 + (5-(-1))^2}](https://tex.z-dn.net/?f=%20%5Csqrt%7B%28-3-1%29%5E2%20%2B%20%285-%28-1%29%29%5E2%7D)
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Simplify:
</span>
![\sqrt{(-3-1)^2 + (5+1))^2}](https://tex.z-dn.net/?f=%20%5Csqrt%7B%28-3-1%29%5E2%20%2B%20%285%2B1%29%29%5E2%7D)
![\sqrt{-4^2+ 6^2}](https://tex.z-dn.net/?f=%20%5Csqrt%7B-4%5E2%2B%206%5E2%7D)
![\sqrt{16+36}](https://tex.z-dn.net/?f=%20%5Csqrt%7B16%2B36%7D)
![\sqrt{52}](https://tex.z-dn.net/?f=%20%5Csqrt%7B52%7D)
You can leave it as:
![\sqrt{52}](https://tex.z-dn.net/?f=%5Csqrt%7B52%7D)
or in decimal form as: 7.2
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Answer:
7.1 weeks to 68.4 weeks
Step-by-step explanation:
Chebyshev's Theorem states that:
75% of the measures are within 2 standard deviations of the mean.
89% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 38.1
Standard deviation = 10.1
Between what two search times does Chebyshev's Theorem guarantee that we will find at least 89% of the graduates
Between 3 standard deviations of the mean.
So from 38.1 - 3*10.1 = 7.8 weeks to 38.1 + 3*10.1 = 68.4 weeks
The answer is A, this is because as the amount of toppings increases so does the price increase proportionally.