Subtract 36 from both sides making it: -4c-3c=-14
Now subtract -4c and 3c making it: -7c=-14
Now divide by -7 on both sides making it: c=2
There you go
Answer:
A)
Step-by-step explanation:
To find the answer we must solve each of the systems separately. Starting with the first one:
x + y = 2
2x - y = 10
We must find what x or y is equal to and then replace it in the second equation. I'll go with y as it seems easier:
x + y = 2
y = 2 - x
Now that we found y we replace it in the second equation this way. Be careful with the signs, the minus with change our signs:
2x - (2 - x) = 10
2x - 2 + x = 10
3x = 12
x = 12/3
x = 4
Now that we have x, we replace the variable with its value in one of the equations. Again, for simplicity I'll go with the one that seems easier.
4 + y = 2
y = 2 - 4
y = - 2
Based on the given situation, if x is number of kilograms of lobster, you can write the following expressions:
51 + 5x cost in the first restaurant
33 + 8x cost in the second restaurant
In order to determine the value of x which makes the cost the same in both restaurants, equal the previous expressions and solve for x:
51 + 5x = 33 + 8x subtract 33 both sides and 5x subtract both sides
51 - 33 = 8x - 5x simplify
18 = 3x divide by 3 both sides
18/3 = x
6 = x
x = 6
Hence, the weight of the lobster is 6 kg.
The cost of the dinner is:
51 + 5(6) = 51 + 30 = 81
Hence, the cost of the dinner is $81
Answer:
15
Step-by-step explanation:
the answer is 15 because if the result of a number having 5 subtracted from it is 10 then that's the answer.
Answer:
0
Step-by-step explanation:
total number of balls = 3+5+2= 10
Probability of getting red P(R) = 3/10
Probability of getting white P(W) = 5/10
Probability of getting black P(B) = 2/10
for each red ball drawn you win $6 and for each black ball drawn you loose $9 dollars
E(X)= 6×3/10 +0×5/10 -9×2/10= 0
E(X)= 0
