All categories

3 years ago

In this exercise, we show that the orthogonal distance d from the plane p with equation

1 answer:

3 0

Use the cross product to find the orthogonal vector, solve the parametric equation to see at which (t) the point + orthogonal vector intersects the plane, the distance is (t) * norm of vector

You might be interested in

6. Look at this graph: Is this relation a function? Yes or no

zmey [24]

Both are not functions because functions cannot have repeating x values

3 0

3 years ago

Read 2 more answers

Question:

Tamiku [17]

Answer:

Step-by-step explanation:

$3x^2 + 12x + 6 = 0\\\\a=3\,,\ b=12\,,\ c=6\\\\\\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\ x=\dfrac{-12\pm\sqrt{12^2-4\cdot3\cdot6}}{2\cdot3}=\dfrac{-12\pm\sqrt{144-72}}{2\cdot3}=\dfrac{-12\pm\sqrt{72}}{2\cdot3}=\dfrac{-12\pm6\sqrt{2}}{6}\\\\x_1=\dfrac{6(-2+\sqrt{2})}{6}=-2+\sqrt2\\\\x_2=\dfrac{6(-2-\sqrt{2})}{6}=-2-\sqrt2$

8 0

3 years ago

Which is a greater slope 3 or -4

castortr0y [4]

Answer:

3 is greater than -4, but the line with slope -4 is steeper than the line with slope 3.

Step-by-step explanation:

3 is greater than -4, so strictly speaking, a slope of 3 is greater than a slope of -4.

On the other hand, the steepness of a line depends on the absolute value of the slope.

|3| = 3

|-4| = 4

Since 4 > 3, the line with slope -4 is steeper than the line with slope 3.

Answer: 3 is greater than -4, but the line with slope -4 is steeper than the line with slope 3.

4 0

3 years ago

At the 2007 Math Olympics, Team Canada won 17 out of a possible 100 medals. Which one of the following is closest to the fractio

irinina [24]

Answer:1/8

Step-by-step explanation:

3 0

3 years ago

Solve for x.<br> 4x +4=12

PolarNik [594]

Answer:

x = 2

Step-by-step explanation:

4x +4=12

-4. -4

4x.= 8

divide both saide by 4

x. = 2

8 0

3 years ago