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Alja [10]
3 years ago
10

makayla's local movie theater has a movie goer club that charges an annual registration fee of $25. however, movie tickets are d

iscounted for member at $6.00 per ticket, instead of the regular $9.00 per ticket. let m equal the number of movie tickets makayla purchases in a year. write a function to model the amount of money makayla spent on going to the movies during the year she joined the club the domain is represented by
Mathematics
1 answer:
marissa [1.9K]3 years ago
4 0

Answer:

C(m) = 25 + 6m  and m ≥ 0.

Step-by-step explanation:

After joining the moviegoer club, Makayla charged an annual registration fee of $25. but, movie tickets are charged for members at $6.00 per ticket.

Let us assume that Makayla purchased m number of movie tickets in a year since he joined the club then the function that models the total cost for Makayla's movie ticket is given by  

C(m) = 25 + 6m  

The domain of the function is represented by m ≥ 0. (Answer)

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EOC Review
lana [24]

Answer:

0ft and 60ft

Step-by-step explanation:

Given

The attached function

Required

Determine the valid values of the domain of the function

To do this, we simply consider the starting point and the end point of the trajectory on the x-axis (i.e. the horizontal distance).

From the attached graph, the horizontal distance starts from 0 and ends at 180.

This implies that the domain is: 0 \le x \le 180

From the options, the values that fall in this bracket are 0ft and 60ft

3 0
2 years ago
Some body can help me with a geometric mean maze
Mars2501 [29]

Answer:

See explanation

Step-by-step explanation:

Theorem 1: The length of the altitude to the hypotenuse of a right triangle is the geometric mean of the lengths of the segments of the hypotenuse.

Theorem 2: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

1. Start point: By the 1st theorem,

x^2=25\cdot (49-25)=25\cdot 24=5^2\cdot 2^2\cdot 6\Rightarrow x=5\cdot 2\cdot \sqrt{6}=10\sqrt{6}.

2. South-East point from the Start: By the 2nd theorem,

x^2=40\cdot (40+5)=4\cdot 5\cdot 2\cdot 9\cdot 5\Rightarrow x=2\cdot 5\cdot 3\cdot \sqrt{2}=30\sqrt{2}.

3. West point from the previous: By the 2nd theorem,

x^2=(32-20)\cdot 32=4\cdot 3\cdot 16\cdot 2\Rightarrow x=2\cdot 4\cdot \sqrt{6}=8\sqrt{6}.

4. West point from the previous: By the 1st theorem,

9^2=x\cdot 15\Rightarrow x=\dfrac{81}{15}=\dfrac{27}{5}=5.4.

5. West point from the previous: By the 2nd theorem,

10^2=8\cdot (8+x)\Rightarrow 8+x=12.5,\ x=4.5.

6. North point from the previous: By the 1st theorem,

x^2=48\cdot 6=6\cdot 4\cdot 2\cdot 6\Rightarrow x=6\cdot 2\cdot \sqrt{2}=12\sqrt{2}.

7. East point from the previous: By the 2nd theorem,

x^2=22.5\cdot 30=225\cdot 3\Rightarrow x=15\sqrt{3}.

8. North point from the previous: By the 1st theorem,

x^2=7.5\cdot 36=270\Rightarrow x=3\sqrt{30}.

8. West point from the previous: By the 2nd theorem,

x^2=12.5\cdot (12.5+13.5)=12.5\cdot 26=25\cdot 13\Rightarrow x=5\sqrt{13}.

9. North point from the previous: By the 1st theorem,

12^2=x\cdot 30\Rightarrow x=\dfrac{144}{30}=4.8.

101. East point from the previous: By the 1st theorem,

6^2=1.6\cdot (x-1.6)\Rightarrow x-1.6=22.5,\ x=24.1.

11. East point from the previous: By the 2nd theorem,

20^2=32\cdot (32-x)\Rightarrow 32-x=12.5,\ x=19.5.

12. South-east point from the previous: By the 2nd theorem,

18^2=x\cdot 21.6\Rightarrow x=15.

13. North point=The end.

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%28%20-%203%29%20%7B%7D%5E%7B2%7D%20.%28%20-%203%29%20%20%7B%7D%5E%7B2%7D%20" id="TexFormula1"
liq [111]
The answer is 81. since (-3)^2 is 9. Therefore, 9x9=81.
4 0
3 years ago
Plz answer this i need help its done today
olga55 [171]

Answer:

1) 1/10

2) 1/2

3) 1/5

Step-by-step explanation:

1)

1 favorable outcome and 10 total outcomes.

P(3) = \frac{1}{10}

2)

5 favorable outcomes and 10 total outcomes

P(even) = \frac{5}{10} = \frac{1}{2}

3)

2 favorable outcomes and 10 total outcomes

P(multiples\ of\ 5) = \frac{2}{10} = \frac{1}{5}

3 0
3 years ago
Given G (1,2) and K(8,12) what does it mean to find the point P on line GK such that 3 (GP) = 2 (PK)?
Lunna [17]
Check the picture below.

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3 years ago
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