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ddd [48]
2 years ago
11

Determine if S could lie on the perpendicular bisector of QR with the given coordinates

Mathematics
1 answer:
Alex2 years ago
5 0

Step-by-step explanation:

The distance between two points, and is given by:

The endpoints are: Q(-5, -1), R(3, 7)

Point S is (4,-2).

The distance of S to Q is:

The distance of S to R is:

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Read 2 more answers
Which statement is true?​
love history [14]
<h2>Hello!</h2>

The answer is:

The second option,

(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }

<h2>Why?</h2>

Discarding each given option in order to find the correct one, we have:

<h2>First option,</h2>

\sqrt[m]{x}\sqrt[m]{y}=\sqrt[2m]{xy}

The statement is false, the correct form of the statement (according to the property of roots) is:

\sqrt[m]{x}\sqrt[m]{y}=\sqrt[m]{xy}

<h2>Second option,</h2>

(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }

The statement is true, we can prove it by using the following properties of exponents:

(a^{b})^{c}=a^{bc}

\sqrt[n]{x^{m} }=x^{\frac{m}{n} }

We are given the expression:

(\sqrt[m]{x^{a} } )^{b}

So, applying the properties, we have:

(\sqrt[m]{x^{a} } )^{b}=(x^{\frac{a}{m}})^{b}=x^{\frac{ab}{m}}\\\\x^{\frac{ab}{m}}=\sqrt[m]{x^{ab} }

Hence,

(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }

<h2>Third option,</h2>

a\sqrt[n]{x}+b\sqrt[n]{x}=ab\sqrt[n]{x}

The statement is false, the correct form of the statement (according to the property of roots) is:

a\sqrt[n]{x}+b\sqrt[n]{x}=(a+b)\sqrt[n]{x}

<h2>Fourth option,</h2>

\frac{\sqrt[m]{x} }{\sqrt[m]{y}}=m\sqrt{xy}

The statement is false, the correct form of the statement (according to the property of roots) is:

\frac{\sqrt[m]{x} }{\sqrt[m]{y}}=\sqrt[m]{\frac{x}{y} }

Hence, the answer is, the statement that is true is the second statement:

(\sqrt[m]{x^{a} } )^{b}=\sqrt[m]{x^{ab} }

Have a nice day!

6 0
3 years ago
A circle has a diameter of 12 units, and its center lies on the x-axis. what could be the equation of the circle? check all that
wariber [46]

The equation of a circle with radius of 6 units and center on the x axis could be (x - 6)² + y² = 36

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

The circle has a diameter of 12 units. Hence, radius = 12/2 = 6 units.

The center of the circle is at x axis (*, 0), the equation could be:

(x - 6)² + (y - 0)² = 6²

(x - 6)² + y² = 36

The equation of a circle with radius of 6 units and center on the x axis could be (x - 6)² + y² = 36

Find out more on equation at: brainly.com/question/2972832

#SPJ4

5 0
2 years ago
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