Answer:
detailed
Step-by-step explanation:
answer
Answer: The required solution is
Step-by-step explanation: We are given to solve the following differential equation :
Let us consider that
be an auxiliary solution of equation (i).
Then, we have
Substituting these values in equation (i), we get
![m^2e^{mt}+10me^{mt}+25e^{mt}=0\\\\\Rightarrow (m^2+10y+25)e^{mt}=0\\\\\Rightarrow m^2+10m+25=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow m^2+2\times m\times5+5^2=0\\\\\Rightarrow (m+5)^2=0\\\\\Rightarrow m=-5,-5.](https://tex.z-dn.net/?f=m%5E2e%5E%7Bmt%7D%2B10me%5E%7Bmt%7D%2B25e%5E%7Bmt%7D%3D0%5C%5C%5C%5C%5CRightarrow%20%28m%5E2%2B10y%2B25%29e%5E%7Bmt%7D%3D0%5C%5C%5C%5C%5CRightarrow%20m%5E2%2B10m%2B25%3D0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~%5B%5Ctextup%7Bsince%20%7De%5E%7Bmt%7D%5Cneq0%5D%5C%5C%5C%5C%5CRightarrow%20m%5E2%2B2%5Ctimes%20m%5Ctimes5%2B5%5E2%3D0%5C%5C%5C%5C%5CRightarrow%20%28m%2B5%29%5E2%3D0%5C%5C%5C%5C%5CRightarrow%20m%3D-5%2C-5.)
So, the general solution of the given equation is
Differentiating with respect to t, we get
According to the given conditions, we have
and
Thus, the required solution is
Answer:
15.59
Step-by-step explanation:
The answer is 15.59 because to find the area of an equilateral triangle, you need to multiply the height by the length. In this scenario, the length is 6, and we need to find the height. Since we know that all of the sides of the equilateral triangle are 6, we can put a line dividing the equilateral triangle exactly in half as our height. This will form 2 triangles, and each of them will have a length of 3, and a slant height of 6. They would also be right triangles. Now, with this information you can do pythageroum thereom to find the height:: 3^2 + h^2 = 6^2. So, h = √27. Now, to find the area of a triangle, you must multiply the length by the height and then divide by 2. So (6 • √27)/2 is equal to 15.5884572681, which rounded is equivalent to 15.59. So the answer is 15.59.
Answer:
3 is a function.
1 and 2 are not.
Step-by-step explanation:
1 and 2 are not functions because we can draw a vertical line which passes through more than one point on the graphs.
You cant do this on graph 3 so it is a function.
composite, When a number has more than two factors it is called a composite number.
