Question

What are the zeroes of the function y=3(x-a)(x+b) in terms of a and b?

Answer 1

Answer:

a, -b

Step-by-step explanation:

When x is a, the function becomes

$f(a)=3(a-a)(a+b)$

as you see, a-a is 0, and as your whole function is multiplied by this, it makes it 0.

$f(-b)=3(-b-a)(-b+b)$

As you see -b+b is 0, and once again, this would make the whole function 0.