What are the zeroes of the function y=3(x-a)(x+b) in terms of a and b?

Mathematics

1 answer:

juin [17]3 years ago

4 0

Answer:

a, -b

Step-by-step explanation:

When x is a, the function becomes

$f(a)=3(a-a)(a+b)$

as you see, a-a is 0, and as your whole function is multiplied by this, it makes it 0.

$f(-b)=3(-b-a)(-b+b)$

As you see -b+b is 0, and once again, this would make the whole function 0.

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Given the function f(x) = 3x + 1, what is the value of f(-2/3)? show work

Marta_Voda [28]

Answer:

f(-2/3) = -1

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
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Left to Right

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Step-by-step explanation:

Step 1: Define

f(x) = 3x + 1

f(-2/3) is x = -2/3

Step 2: Evaluate

Substitute: f(-2/3) = 3(-2/3) + 1
Multiply: f(-2/3) = -2 + 1
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2 years ago

On average, the merchandise shop sells 80 CDs for every 1 vinyl record. Estimate how many vinyl records they are likely to sell

sp2606 [1]

The merchandise shop sells 80 CDs for every 1 vinyl record. We have to find how many vinyl records they are likely to sell if the merchandise shop sells 760 CDs:
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3 years ago

Read 2 more answers

4x−3=16=4(x−3)=16 Do they have the same solution?

AnnZ [28]

Answer:

Step-by-step explanation:

4x -3 = 16

x=19/4

4(x-3) = 16: Distribute the number in the parenthesis with 4 and you get:

4x-12=16

x=7