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Trava [24]
3 years ago
5

A bag contains 8 black marbles and 20 yellow marbles. You reach into the bag and pull out a black marble. Then you reach into th

e bag and pull out another marble. What is the probability that the second marble is yellow?
Mathematics
1 answer:
sveticcg [70]3 years ago
6 0
You have a bag containing 8 + 20 = 28 marbles.

After you pull a black marble you have 28 - 1 = 27 remaining marbles.

There are 20 yellow marbles in the bag.

The probability of pulling a yellow marble is now

\frac{20}{27} which \: is \: approximately \: equal \: to \\ 74.07\%
You might be interested in
Max measures the diagonal of a square room to be 32feet find the perimeter and area of the room round answers to the nearest ten
Rasek [7]
Hello!

To find the side length of a square with the diagonal you use the equation

a =  \sqrt{2}  \frac{d}{2}

a is side length
d is diagonal length

Put in the values you know

a =  \sqrt{2} *  \frac{32}{2}

Divide

a =  \sqrt{2} * 16

Multiply

a = 22.6

All the sides are 22.6 feet

Add all the sides

22.6 + 22.6 + 22.6 + 22.6 = 90.4

The answer is 90.4

Hope this helps!
3 0
3 years ago
Guyssss I’m confuseddddd
rosijanka [135]

Answer:

0 > -5

Step-by-step explanation:

9w - 4w + 6 > 1 + 5w

add the similar variables

5w + 6  > 1 + 5w

subtract  6 from both sides

5w + 6  > 1 + 5w

       -6     -6

5w > 5w - 5

simplify

5w > 5w -5

subtract 5 w from both sides

5w > 5w -5

-5w    -5w

simplify

= 0 > -5

4 0
2 years ago
What is the constant of proportionality in this graph?
lana [24]

Answer:

one half or 1/2

Step-by-step explanation:

do your rise over your run on the graph.

7 0
3 years ago
As an estimation we are told 5 miles is 8 km. <br> Convert 57.5 miles to km.
Elena L [17]

Answer:

5 miles=8km

1miles=8/5=1.6km

57.5 miles=(57.5×1.6)km

=92km

8 0
3 years ago
Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y
Zina [86]

Answer:

Step-by-step explanation:

The given differential equation is:

x^3y'' + 2x^2y' + 4y

the main task here is to determine the singular points of the given differential equation and Classify each singular point as regular or irregular.

So, for a regular singular point ;  x=x_o is  located at the first power in the denominator of P(x) likewise at the Q(x) in the second power of the denominator. If that is not the case, then it is termed as an irregular singular point.

Let first convert it to standard form by dividing through with x³

y'' + \dfrac{2x^2y'}{x^3} + \dfrac{4y}{x^3} =0

y'' + \dfrac{2y'}{x} + \dfrac{4y}{x^3} =0

The standard form of the differential equation is :

\dfrac{d^2y}{dy} + P(x) \dfrac{dy}{dx}+Q(x)y =0

Thus;

P(x) = \dfrac{2}{x}

Q(x) = \dfrac{4}{x^3}

The zeros of x,x^3  is 0

Therefore , the singular points of above given differential equation is 0

Classify each singular point as regular or irregular.

Let p(x) = xP(x)    and q(x) = x²Q(x)

p(x) = xP(x)

p(x) = x*\dfrac{2}{x}

p(x) = 2

q(x) = x²Q(x)

q(x) = x^2 * \dfrac{4}{x^3}

q(x) =\dfrac{4}{x}

The function (f) is analytic if at a given point a it is represented by power series in x-a either with a positive or infinite radius of convergence.

Thus ; from above; we can say that q(x) is not analytic  at x = 0

Q(x) = \dfrac{4}{x^3}  do not satisfy the condition,at most to the second power in the denominator of Q(x).

Thus, the point x =0 is an irregular singular point

6 0
3 years ago
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