All categories

3 years ago

27. Suppose the hare runs 600 inches per second and the tortoise runs

Mathematics

1 answer:

klemol [59]3 years ago

3 0

Answer:

A. 3t = 600t + 12,000

Step-by-step explanation:

It would be A because if the tortoise is going 3 inches per second then that would be your ending point and since the hare is going 600 inches per second then you would have to add 12,000 to 600t because the tortoise is 12,000 inches in front of the hare.

You might be interested in

A triangle whose angles have measures x x+5 and x+10

nirvana33 [79]

the correct question is
A triangle whose angles have measures x x+5 and x+10.How do you find the measure of each angle?

we know that
The Sum of internal angles of any triangle = 180∘
so
[x+(x+5)+(x+10)]=180---------------> 3x+15=180----------> 3x=165-------> x=55°

the answer is
the measure of each angle is
x=55°
x+5=60°
x+10=65°

4 0

3 years ago

Given f(x) = 4(x - 8), determine the value of f(10).

Komok [63]

Answer:

f(x) = 4(x - 8)

4 (10 -8) = 8

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Which term describes a function in which the y-values form a geometric sequence

romanna [79]

The geometric sequence is a sequence in which the proceeding number is equal to the preceeding number multiplied by a ratio. The expression that represents this sequence is an = a1*r^(n-1) where r is the ratio and n is an integer. This type of formula is exponential

8 0

3 years ago

23. A certain type of gasoline is supposed to have a mean octane rating of at least 90. Suppose measurements are taken on of 5 r

Nostrana [21]

Answer:

a) $p_v =P(Z$

b) Since $p_v$ we can reject the null hypothesis at the significance level given. So based on this we can commit type of Error I.

Because Type I error " is the rejection of a true null hypothesis".

c) $P(\bar X >90)=1-P(Z$

$1-P(Z$

d) For this case we need a z score that accumulates 0.02 of the area on the right tail and 0.98 on the left tail and this value is z=2.054

And we can use this formula:

$2.054=\frac{90-89}{\frac{0.8}{\sqrt{n}}}$

And if we solve for n we got:

$n = (\frac{2.054 *0.8}{1})^2=2.7 \approx 3$

Step-by-step explanation:

Previous concepts and data given

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

We can calculate the sample mean and deviation with the following formulas:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}$

$\bar X=88.96$ represent the sample mean

$s=1.011$ represent the sample standard deviation

n=5 represent the sample selected

$\alpha$ significance level

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is less than 90, the system of hypothesis would be:

Null hypothesis: $\mu \geq 90$

Alternative hypothesis: $\mu < 90$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{88.96-90}{\frac{0.8}{\sqrt{5}}}=-2.907$

Part a

P-value

First we need to calculate the degrees of freedom given by:

$df=n-1=5-1 = 4$

Then since is a left tailed test the p value would be:

$p_v =P(Z$

Part b

Since $p_v$ we can reject the null hypothesis at the significance level given. So based on this we can commit type of Error I.

Because Type I error " is the rejection of a true null hypothesis".

Part c

We want this probability:

$P(\bar X$

The best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

If we apply this formula to our probability we got this:

$P(\bar X >90)=1-P(Z$

$1-P(Z$

Part d

For this case we need a z score that accumulates 0.02 of the area on the right tail and 0.98 on the left tail and this value is z=2.054

And we can use this formula:

$2.054=\frac{90-89}{\frac{0.8}{\sqrt{n}}}$

And if we solve for n we got:

$n = (\frac{2.054 *0.8}{1})^2=2.7 \approx 3$

7 0

3 years ago

PLEASE HURRY ITS A TEST

AnnyKZ [126]

8+5+8=21 coins in total.
8/21*7/20=
56/420=
2/15. Hope this helps, and PM me if something's not clear!

4 0

3 years ago