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3 years ago

If you answer the question correct and show steps i will mark you brainiest

Mathematics

1 answer:

olasank [31]3 years ago

5 0

Im pretty sure x=4
because, if LO BISECTS NLM then it splits it in half, and if one of the halves is 4 then the other also should be.
im so sorry if its wrong

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Which of the following is an extraneous solution of the square root of -3x-2=x+2

yarga [219]

Answer:

x=-6 is an extraneous solution

Step-by-step explanation:

we have

$\sqrt{-3x-2} =x+2$

squared both sides

$-3x-2=(x+2)^2$

$-3x-2=x^2+4x+4$

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solve the quadratic equation by graphing

The solution is x=-6 and x=-1

see the attached figure

Verify each solution

substitute the value of x in the original expression

For x=-6

$\sqrt{-3(-6)-2} =-6+2$

$\sqrt{16} =-4$

$4=-4$ ----> is not true

Is an extraneous solution

For x=-1

$\sqrt{-3(-1)-2} =-1+2$

$\sqrt{1} =1$

$1=1$ ----> is true

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$BlackSparkles...$