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2 years ago

How to get the number 2016 using math

Mathematics

1 answer:

Lapatulllka [165]2 years ago

6 0

2000 + 16 = 2016

1008 * 2 = 2016

3000 - 984 = 2016

8064 / 4 = 2016

there are 4 different ways

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Describe using complete sentences the purpose of the following three tax forms W4 W2 and 1040

disa [49]

I think with a W2, the employer files it and sends it to you, then you use that W2 to fill out either a W4 or a 1040

6 0

2 years ago

Find the value of the variable. If your answer is not an integer, leave it in simplest radical form.

Fed [463]

It is the square root of 2

6 0

2 years ago

What is equivalent to (3 - 2x) (4x - 7)

bonufazy [111]

Answer:

-8x^2+26x-21

Step-by-step explanation:

(3-2x)(4x-7)

12x-8x^2-21+14x

-8x^2+12x+14x-21

-8x^2+26x-21

7 0

2 years ago

Read 2 more answers

5x +7 y=-17<br> 4x – 3y = -5<br> Substitute.

Bond [772]

Answer:

(x,y) = (-2, -1)

Step-by-step explanation:

We start off by substituting the value of "x".

5x+7y=-17

x=- $\frac{5}{4} + \frac{3}{4}y$

We then solve 5 $5(-\frac{5}{4}+\frac{3}{4}y ) +7y= -17$

y=-1 *Substitute the value of "y"

x= - $-\frac{5}{4}+\frac{3}{4}x(-1)$

x=-2

$\left \{ {{-17=-17} \atop {-5=-5}} \right.$ This works.

5 0

3 years ago

A box of Munchkins contains chocolate and glazed donut holes. If Jacob ate 2 chocolate

neonofarm [45]

Answer:

24 munchkins.

Step-by-step explanation:

Let C be the number of chocolate and D be number of glazed donut holes in the original box.

We are told if Jacob ate 2 chocolate munchkins, then 1/11 of the remaining Munchkins would be chocolate. We can represent this information as:

$C-2=\frac{1}{11}*(C+D-2)...(1)$

We are also told if he instead added 4 glazed Munchkins to the original box, 1/7 of the Munchkins would be chocolate. We can represent this information as:

$C=\frac{1}{7}*(C+D+4)...(2)$

Upon substituting C's value from equation (2) in equation (1) we will get,

$\frac{1}{7}*(C+D+4)-2=\frac{1}{11}*(C+D-2)$

Let us have a common denominator on right side of equation.

$\frac{1}{7}*(C+D+4)-\frac{7*2}{7}=\frac{1}{11}*(C+D-2)$

$\frac{C+D+4-14}{7}=\frac{1}{11}*(C+D-2)$

Multiplying both sides of our equation by 7, we will get,

$7*\frac{C+D-10}{7}=7*\frac{1}{11}*(C+D-2)$

$C+D-10=\frac{7}{11}*(C+D-2)$

Multiplying both sides of our equation by 11, we will get,

$11*(C+D-10)=11*\frac{7}{11}*(C+D-2)$

$11*(C+D-10)=7*(C+D-2)$

$11C+11D-110=7C+7D-14$

$11C-7C+11D-7D=-14+110$

$4C+4D=96$

$4(C+D)=96$

$(C+D)=\frac{96}{4}$

$(C+D)=24$

Therefore, the total number of Munchkins in original box is 24.

3 0

3 years ago