The answer is false because if you attach to triangles together in a way so that the figure would have 4 straight lines, you will get a rectangle. that means half of a rectangle is a triangle, so the area of both cannot be the same even if they have the same base and height.
for example the base and height of both is 3cm and 5cm.
area of the rectangle then would be,
area= base× height
=3cm×5cm=15cmsquared
then the area of the triangle would be,
area= base×height divided by 2
=3cm×5cm÷2= 7.5cm
so your answer is false
hope this helps....
Answer:
The answer to this is: y = (x - 6)² - 28
Step-by-step explanation:
The first step is to make sure the coefficient in front of x² is 1. If it isn't, just divide the whole equation by the coefficient. In this case, you don't need to do any division because you just have x²
Group the first two terms involving x² and x:
(x² - 12x) + 8
Now complete the square as follows:
a. Take the coefficient in front of x --> -12
b. Halve it --> -6
c. Square it --> (-6)² = 36
d. Add this and subtract it
(x² - 12x + 36 - 36) + 8
Take the negative number outside the parentheses:
(x² - 12x + 36) - 36 + 8
(x² - 12x + 36) - 28
The part in parentheses is a perfect square so rewrite it as such. If you need help refer back to step b.
(x - 6)(x - 6) - 28
(x - 6)² - 28
P.S. Vertex form is:
(x - h)² + k
In that form, the vertex is (h, k). In your case, the vertex of the parabola would be (6, -28).
Answer:
y = (x - 6)² - 28
Difference quotient = [f(x+h) - f(x)]/h
[-5(x+h) -3 - (-5x -3)]/h
[-5x -5h -3 + 5x +3]/h
[-5h]/h
-5
