If I remember correctly it should be B because every input has to have 1 output. I apologize if it’s wrong ( I haven’t had those problems since 8th grade I’m currently in 10th)
First one= x=5
second one= x=1/30 or 0.03 or 30^-1
third one= All real numbers or R
fourth one= No solution
Fifth one= All real numbers or R
Sixth one= p=-10/3 or -3 1/3 or -3.3
R is just the symbol for all real numbers. Also know as infinitely many solutions.
Hope this helps ! :) have a good day! Make sure you eat.
7/6 is 1 and 1/6 (1 1/6) as a reduced fraction. 7/6 is an improper fraction. So, how many times does 6 go into 7, it goes into it one time and there is one remainder.
The maximum possible profit = $7068
For given question,
One Microsoft July $72 put contract for a premium of $1.32
The payoff arise from put option is max (K - S, 0) - P
Now it would be maximum at S = 0
And, the maximum payoff is
K - 0 - P
= K - P
= 72 - 1.32
= $70.68
We assume that for each and every contract the number of shares is 100
So, the maximum profit gained from this strategy is
= $70.68 × 100 shares
= $7068
The maximum profit that will be gained from this strategy is $7068
Therefore, the maximum possible profit = $7068
Learn more about the profit here:
brainly.com/question/20165321
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First simplify the equation.
3x+3y= -x+5y
4x=2y
2x=y
y=2x
Means that the y value is 2 times the x value.
answer: C but there are more solutions than just (1,2) and (2,4)
