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Tomtit [17]
3 years ago
8



Mathematics
2 answers:
Ilia_Sergeevich [38]3 years ago
7 0

Answer:

1/2 is the pre image for this

Elis [28]3 years ago
7 0

Answer: the answer is 1/2

Step-by-step explanation:

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Help <br><br> (no files or links) <br><br> (will give brainliest)
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strating up to down 100 50 10 2 5

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3 years ago
Joji earns 3 times as much as Masao. If Joji and Masao earn $4,500.00 together, how much money does Masao earn? a $1,125.00 b $1
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3xMasao=Joji
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3 years ago
The common minimum multiple between <br><br> A) 2,3 and 6<br> B) 8,9 and 12<br> C) -4,2 and 8
Elan Coil [88]
A 2,3 and 6. There you go. :)
8 0
3 years ago
Suppose that Upper X has a discrete uniform distribution f left-parenthesis x right-parenthesis equals StartLayout left-brace1st
emmasim [6.3K]

Answer:

the probability that the sample mean is greater than 2.1 but less than 2.4 is 0.2444

Step-by-step explanation:

Given the data in the question;

x        f(x)         xp(x)               x²p(x)

1         1/3        0.33333        0.33333

2        1/3        0.66667        1.33333

3        1/3        1.00000        3.0000

∑                    2.0000          4.6667

∑(xp(x)) = 2

∑(x²p(x)) = 4.6667

Variance σ² = ∑(x²) - ∑(x)² = 4.6667 - (2)² = 4.6667 - 4 = 0.6667

standard deviation σ = √variance = √0.6667 = 0.8165

Now since, n = 33 which is greater than 30, we can use normal approximation

for normal distribution z score ( x-μ)/σ

mean μ = 2

standard deviation = 0.817

sample size n = 33

standard of error σₓ = σ/√n = 0.817/√33 = 0.1422

so probability will be;

p( 2.1  < X < 2.4 ) = p(( 2.1-2)/0.1422) <  x"-μ/σₓ  <  p(( 2.4-2)/0.1422)

= 0.70 < Z < 2.81    

=  1 - ( 0.703 < Z < 2.812 )

FROM Z-SC0RE TABLE

=  1 - ( 0.25804 + 0.49752 )

= 1 - 0.75556

p( 2.1  < X < 2.4 ) = 0.2444

Therefore,  the probability that the sample mean is greater than 2.1 but less than 2.4 is 0.2444

7 0
3 years ago
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