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Tomtit [17]
3 years ago
8



Mathematics
2 answers:
Ilia_Sergeevich [38]3 years ago
7 0

Answer:

1/2 is the pre image for this

Elis [28]3 years ago
7 0

Answer: the answer is 1/2

Step-by-step explanation:

You might be interested in
The density of Venus, compared to Earth having a density of 1,
guapka [62]

Answer:

Mercury

Step-by-step explanation:

We'll translate this into ratios.

First, V:E = 0.943:1

Then, M:E = 0.983:1

We already have their density in terms earth's density. They are in the same unit. So, we can compare them directly, with greater ratio means greater density. It's clear that Mercury has the greater density.

6 0
4 years ago
What is 100×100?<br><br> can someone help me
Hunter-Best [27]
100 times 100
When you want to multiply 100 by 100, count up all the zeros first.
There are 2 zeros in one 100 and 4 zeros in two 100's.
Since there are 4 zeros, that means 100 • 100 is a 1 followed by 4 zeros.
This means 100 • 100 = 10,000

100 multiplied by 100 is 10,000 (ten thousand)

Hope this helps!
6 0
3 years ago
Read 2 more answers
5,4,16/5 find the 10th term
Aleks04 [339]

the sequence is 25/4(4/5)^x

plug in 10 for x to get your solution:

25/4(4/5)^10=4^9/5^8

7 0
3 years ago
What are the amplitude, period, and midline of f(x)=-4 cos (2x-n)+3?
tangare [24]
To find the amplitude and period you need to be familiar with the following equation. Also you need to know that the standard cos has a period of 2\pi and the midline is a line that runs between the max and min of the y-values of the function.

Equations:
f(x) = A cos(Bx +C) + D
f(x) = -4 cos(2x -n) + 3

A = amplitude = |-4| = 4
B = 2
C = phase shift = n = 0 
D = vertical shift = midline = 3

Amplitude = 4

Find the period:
Period = \frac{2\pi}{B} = \frac{2\pi}{2} = \pi

Find the midline:
We know that the amplitude is 4  so we have a range from -4 to 4. The standard y = cos(x) has its midline at 0 so y = 0. This is also true for y = -4 cos(x). In your equation though, you have a vertical shift of +3 so this changes our midline. With an amplitude of 4, which gives us a range from -4 to 4(our y-values), the shift moves this up by 3 so that means we will have new y-values and a range of -1 to 7. Now we need to find the midline(the middle of our y-values) of our new range. We can find this by using the following formula
Midline = \frac{Y_1 + Y_2}{2} = \frac{-1+ 7}{2} = \frac{6}{2} = 3

Midline:
y = 3

Note, in the following equations that D = 3 = midline

y = A (Bx+C) + D
y = -4 (2x + n) + 3

Also, the picture that is attached is what your equation looks like when graphed.


7 0
3 years ago
What is the answer to this question?
Nitella [24]

Answer:

11x+2

Step-by-step explanation:

4 0
3 years ago
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