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3 years ago

Mathematics

2 answers:

Ilia_Sergeevich [38]3 years ago

7 0

Answer:

1/2 is the pre image for this

Elis [28]3 years ago

7 0

Answer: the answer is 1/2

Step-by-step explanation:

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Suppose you are representing the employees at a large corporation during contract negotiations. You have a list of the salaries

evablogger [386]

Answer:

Median

Step-by-step explanation:

Median is ascertained by arranging a set of data in either ascending or descending order and picking the number that appears In the middle. The measure of center to use for this test is the median because it will represent the employees, it helps to arrange their income accordingly and the central item is determined.

7 0

3 years ago

Use cylindrical coordinates. find the volume of the solid that lies within both the cylinder x2 y2 = 9 and the sphere x2 y2 z2 =

marissa [1.9K]

In Cartesian coordinates, the region is given by $-3\le x\le3$ , $-\sqrt{9-x^2}\le y\le\sqrt{9-x^2}$ , and $-\sqrt{16-x^2-y^2}\le z\le\sqrt{16-x^2-y^2}$ . Converting to cylindrical coordinates, using

$\begin{cases}\mathbf x(r,\theta,\zeta)=r\cos\theta\\\mathbf y(r,\theta,\zeta)=r\sin\theta\\\mathbf z(r,\theta,\zeta)=\zeta\end{cases}$

we get a Jacobian determinant of $r$ , and the region is given in cylindrical coordinates by $0\le\theta\le2\pi$ , $0\le r\le3$ , and $-\sqrt{16-r^2}\le z\le\sqrt{16-r^2}$ .

The volume is then

$\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=3}\int_{z=-\sqrt{16-r^2}}^{z=\sqrt{16-r^2}}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta=\dfrac{4(64-7\sqrt7)\pi}3$