Yes this is correct you did it correct
The ordered pairs which satisfy the equation are (0,2) , (7,19) (-5,17) .
Finding the values of the variables that result in equality is the first step in solving a variable equation.
- The values of the unknown variables that fulfil the equality are the equation's solutions, also known as the variables for which the equation must be solved.
- The two forms of equations are identity equations and conditional equations.
- All feasible values of the variables share the same identity. Only specific instances where the values of the variables coincide can result in the truth of a conditional equation.
- Two phrases are combined into one by using the equals sign ("="). The "left hand side" and "right hand side" of the equation refer to the expressions on each side of the equals sign. It's typical.
At x = 0 the value of y from the equation is :
y = 2
At x = 7 , y =-19
at y=17 , x= -5
Therefore the ordered pairs are :(0,2) , (7,19) (-5,17) .
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Answer:
The correct option is B. 172 square inches
Step-by-step explanation:
Side length of the regular pentagon = 10 inches
Area of the regular pentagon is given by :
Hence, the correct option is B. 172 square inches
bearing in mind that perpendicular lines have negative reciprocal slopes, hmmm what's the slope of the equation above?
![\bf 2x-4y+8=0\implies -4y=-2x-8\implies y = \cfrac{-2x-8}{-4} \\\\\\ y = \cfrac{-2x}{4}-\cfrac{8}{-4}\implies y = \stackrel{\stackrel{m}{\downarrow }}{-\cfrac{1}{2}}x+2\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%202x-4y%2B8%3D0%5Cimplies%20-4y%3D-2x-8%5Cimplies%20y%20%3D%20%5Ccfrac%7B-2x-8%7D%7B-4%7D%20%5C%5C%5C%5C%5C%5C%20y%20%3D%20%5Ccfrac%7B-2x%7D%7B4%7D-%5Ccfrac%7B8%7D%7B-4%7D%5Cimplies%20y%20%3D%20%5Cstackrel%7B%5Cstackrel%7Bm%7D%7B%5Cdownarrow%20%7D%7D%7B-%5Ccfrac%7B1%7D%7B2%7D%7Dx%2B2%5Cqquad%20%5Cimpliedby%20%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20slope-intercept~form%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20y%3D%5Cunderset%7By-intercept%7D%7B%5Cstackrel%7Bslope%5Cqquad%20%7D%7B%5Cstackrel%7B%5Cdownarrow%20%7D%7Bm%7Dx%2B%5Cunderset%7B%5Cuparrow%20%7D%7Bb%7D%7D%7D%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
so we're really looking for the equation of a line whose slope is 2 and runs through (2,-5),
