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icang [17]
3 years ago
13

Cung Pí simplifies

Mathematics
1 answer:
MakcuM [25]3 years ago
6 0

Answer:

sorry PLS the question is not clear I think U missed some parts

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F(x) = x - 4<br>Vertex:<br>y-intercept:<br>x-intercept(s);​
USPshnik [31]
Yes this is correct you did it correct
6 0
3 years ago
Complete the order pairs below so they satisfy the equation Y=-3x+2Complete the order pairs (0,__) (7,__) (__,17)
Alchen [17]

The ordered pairs which satisfy the equation are  (0,2) , (7,19) (-5,17) .

Finding the values of the variables that result in equality is the first step in solving a variable equation.

  • The values of the unknown variables that fulfil the equality are the equation's solutions, also known as the variables for which the equation must be solved.
  • The two forms of equations are identity equations and conditional equations.
  • All feasible values of the variables share the same identity. Only specific instances where the values of the variables coincide can result in the truth of a conditional equation.
  • Two phrases are combined into one by using the equals sign ("="). The "left hand side" and "right hand side" of the equation refer to the expressions on each side of the equals sign. It's typical.

At x = 0 the value of y from the equation is :

y = 2

At x = 7 , y =-19

at y=17 , x= -5

Therefore the ordered pairs are :(0,2) , (7,19) (-5,17) .

To learn more about equation visit:

brainly.com/question/10413253

#SPJ1

8 0
1 year ago
What is the area of a regular pentagon with a side length of 10 inches and a distance from the center to a vertex of 10 inches?
algol13

Answer:  

The correct option is B. 172 square inches

Step-by-step explanation:

Side length of the regular pentagon = 10 inches

Area of the regular pentagon is given by :

Area = \frac{1}{4}(\sqrt{25+10\sqrt{5}})\cdot side^2\\\\\implies Area = \frac{1}{4}(\sqrt{25+10\sqrt{5}})\cdot 10^2\\\\\implies Area = \frac{1}{4}(\sqrt{25+10\sqrt{5}}) \cdot 100\\\\\implies Area =25\times (\sqrt{25+10\sqrt{5}})\\\\\implies Area = 172.04 \:\:inches^2\\\\\bf\implies Area\approx 172 \:\:inches^2

Hence, the correct option is B. 172 square inches

4 0
3 years ago
What's -3 = n +9 for algebra
Leokris [45]
The answer is clearly 6
3 0
3 years ago
Read 2 more answers
write and equation for the line in point-slope form that passes through (2,-5) and is perpendicular to the line 2x-4y+8=0​
Ivenika [448]

bearing in mind that perpendicular lines have negative reciprocal slopes, hmmm what's the slope of the equation above?

\bf 2x-4y+8=0\implies -4y=-2x-8\implies y = \cfrac{-2x-8}{-4} \\\\\\ y = \cfrac{-2x}{4}-\cfrac{8}{-4}\implies y = \stackrel{\stackrel{m}{\downarrow }}{-\cfrac{1}{2}}x+2\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-\cfrac{1}{2}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{2}{1}}\qquad \stackrel{negative~reciprocal}{\cfrac{2}{1}\implies 2}}

so we're really looking for the equation of a line whose slope is 2 and runs through (2,-5),

\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{-5})~\hspace{10em} \stackrel{slope}{m}\implies 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-5)}=\stackrel{m}{2}(x-\stackrel{x_1}{2}) \\\\\\ y+5=2x-4\implies y=2x-9

4 0
3 years ago
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