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ipn [44]
3 years ago
7

As a medication, Chang's doctor prescribed him a drug with serious restrictions. However, Chang started overdosing on it. This a

ct had severe
Implications on his physical and mental state. To which category could this drug belong?
Chemistry
1 answer:
ipn [44]3 years ago
5 0

Answer: Schedule (2) two drug

Explanation: Although it’s virtually difficult or impossible to design a set of defining drug classification standards because even experts have struggled on which drugs should be and not be on a particular schedule but drugs are generally categorised based on their abuse rate (misuse and physical dependency) and their medical use. Drugs with no medical use and higher abuse rate which has physical and mental implications are placed under schedule one, drugs with medical use but also higher abuse rate with physical and mental implications are placed under schedule two, drugs with lower or moderate abuse rate are placed under schedule three, drugs with low potential for dependency are place under schedule four and drugs which are mostly use for antidiarrheal, analgesic and antitussive are placed under schedule five.

Chang's drug has medical use because it was prescribed by his doctor, it also has a high abuse rate because he started overdosing on them which led to a severe physical and mental implications.

Therefore Cheng's drugs will mostly likely be categorised as a schedule (2) two drug.

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The scientific method is the name of the process scientists use to gain knowledge about the physical world.

The scientific method is a systematic approach into the study of nature. It follows the following processes:

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The balanced redox reactions for the sequential reduction of vanadium are given below.
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Answer : 0.0392 grams of Zn metal would be required to completely reduced the vanadium.

Explanation :

Let us rewrite the given equations again.

2VO_{2}^{+} (aq)+ 4H^{+}(aq) + Zn (s)\rightarrow 2VO^{2+}(aq)+Zn^{2+}+2H2O(l)2VO^{2+}(aq)+ 4H^{+}(aq) + Zn (s)\rightarrow 2V^{3+} (aq)+Zn^{2+}+2H2O(l)

2V^{3+} (aq)+ Zn (s)\rightarrow 2V^{2+}(aq)+Zn^{2+}(aq)

On adding above equations, we get the following combined equation.

2VO_{2}^{+} (aq)+ 8H^{+} (aq) + 3Zn (s)\rightarrow 2V^{2+}(aq)+3Zn^{2+}(aq)+4H_{2}O(l)

We have 12.1 mL of 0.033 M solution of VO₂⁺.

Let us find the moles of VO₂⁺ from this information.

12.1 mL \times \frac{1L}{1000mL}\times \frac{0.033mol}{L}=0.0003993mol NO_{2}^{+}

From the combined equation, we can see that the mole ratio of VO₂⁺ to Zn is 2:3.

Let us use this as a conversion factor to find the moles of Zn.

0.0003993mol NO_{2}^{+}\times \frac{3mol Zn}{2molNO_{2}^{+}}=0.00059895mol Zn

Let us convert the moles of Zn to grams of Zn using molar mass of Zn.

Molar mass of Zn is 65.38 g/mol.

0.00059895mol Zn\times \frac{65.38gZn}{1molZn}=0.0392gZn

We need 0.0392 grams of Zn metal to completely reduce vanadium.

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