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trapecia [35]
3 years ago
14

Describe the law of conservation of mass and how it applies to chemical reactions.

Chemistry
1 answer:
Lera25 [3.4K]3 years ago
7 0

Answer:

the law of conservation of mass is whatever goes into a reaction comes out nothing is lost or gianed.

Explanation:

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2NO(g) N2(g) + O2(g); Keq = 2.1 × 1030 What does the value of the equilibrium constant indicate?
olga_2 [115]
The equilibrium constant is a value which represents the equilibrium of a reaction. It is a reaction quotient when the reaction reached equilibrium. If Keq is greater than 1, the mixture contains mostly the products. On the other hand, if Keq is less than 1, the mixture contains the reactants. For this case, the mixture contains mostly products.
7 0
3 years ago
The simplest type of stream cipher, one in which one letter or character is exchanged for another, is known as what?
QveST [7]

Answer: This is known as substitution cipher.

Explanation:

5 0
2 years ago
True or False: If this was a cooling
denpristay [2]

Answer:

True

Explanation:

5 0
3 years ago
The combustion of a sample of butane, C4H10 (lighter fluid), produced 2.46 grams of water.
avanturin [10]

a. 0.137

b. 0.0274

c. 1.5892 g

d. 0.1781

e. 5.6992 g

<h3>Further explanation</h3>

Given

Reaction

2 C4H10 + 13O2 -------> 8CO2 + 10H2O

2.46 g of water

Required

moles and mass

Solution

a. moles of water :

2.46 g : 18 g/mol = 0.137

b. moles of butane :

= 2/10 x mol water

= 2/10 x 0.137

= 0.0274

c. mass of butane :

= 0.0274 x 58 g/mol

= 1.5892 g

d. moles of oxygen :

= 13/2 x mol butane

= 13/2 x 0.0274

= 0.1781

e. mass of oxygen :

= 0.1781 x 32 g/mol

= 5.6992 g

6 0
3 years ago
4. ¿Cuál es la resistencia de un alambre de
Artemon [7]

Answer:

R=0.0438 Ω

Explicación:

1) Hallar el área o sección del conductor de cobre, usando esta fórmula:

                                      A=π.r² (Pi x radio al cuadrado)

Debido a que conocemos el diámetro (1.5mm) su radio es la mitad de esto es decir 0.75mm, y lo sustituimos en la fórmula:

                                      A=π.(0.75mm)²

                                      A=π(0.5625mm²)

                                      A=1.7671mm²

2) La resistividad del cobre es: rho = 0,0172 y la incluimos en la fórmula siguiente:

                                      R=p  

                                      R=0,0172Ω  x  

Simplificamos:

R=

El resultado es:

R=0.0438 Ω

Explanation:

5 0
3 years ago
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