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3 years ago

Please help with these questions ASAP will give brainlist!! CHEMISTRY

Chemistry

1 answer:

Irina18 [472]3 years ago

4 0

Answer:

Question 1 is 21.0g

Explanation:

50 x 4.18 x 3.1 / 0.444 / 69.6= 21.0

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A hot metal plate at 150°C has been placed in air at room temperature. Which event would most likely take place over the next fe

Inga [223]

Answer:

The air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down.

Explanation:

As molecules heat they begin to move faster. The heat from the metal plate will make the molecules at room temperature move faster. And the room temperature makes the hot place cool, making the hot plate molecules slow down.

To visualize this, you can use this link

https://phet.colorado.edu/en/simulations/gas-properties

click the play button to activate the activity

7 0

2 years ago

What is the complete set of quantum numbers for the fifth electron added to a hydrogen ion?

N76 [4]

1s2 2s2 2p1

fifth electron is in 2p orbital

so answer is 2 2 -1 -1/2 , or 2 2 -1 1/2

*1/2 and -1/2 are spins, so they are interchangeable when writing the first electron in the ml

8 0

3 years ago

I still need a bit of help.

Ostrovityanka [42]

H. The atom would no longer be aluminum
If you added a proton to an atom of aluminum it would become a silicone ion

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3 years ago

Hydrocyanic acid, HCN, is a weak acid. (a) Write the chemical equation for the dissociation of HCN in water. (b) Identify the Br

12345 [234]

Answer: a) $HCN(aq.)+H_2O\rightleftharoons H_3O^+(aq.)+CN^-(aq.)$

b) $HCN$ : acid $CN^-$ :conjugate base.

And, $H_2O$ : base $H_3O^+$ : conjugate acid.

c) $HCN(aq.)+NaOH(aq)\rightleftharoons NaCN(aq.)+H_2O(l)$

d) $NaCN(aq)\rightarrow Na^+(aq.)+CN^-(aq)$

e) $NaCN(aq)+HCl(aq)\rightarrow NaCl(aq.)+HCN(aq)$

Explanation:

a) Weak acid is defined as the acid which does not completely dissociates when dissolved in water. They have high pH. These releases $H^+$ ions in their aqueous states.

The equation for the dissociation of $HCN$ acid is given by:

$HCN(aq.)+H_2O\rightleftharoons H_3O^+(aq.)+CN^-(aq.)$

b) According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

For the given chemical equation:

$HCN$ is loosing a proton, thus it is considered as an acid and after losing a proton, it forms $CN^-$ which is a conjugate base.

And, $H_2O$ is gaining a proton, thus it is considered as a base and after gaining a proton, it forms $H_3O^+$ which is a conjugate acid.

c) Neutralization reaction is a reaction in which an acid reacts with base to produce salt and water.

$HCN(aq.)+NaOH(aq)\rightarrow NaCN(aq.)+H_2O(l)$