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Option B:
The expression equivalent to |a| ≤ 5 is a ≥ -5 and a ≤ 5.
Solution:
Given expression:
To find the equivalent expression for the given expression.
Apply absolute value rule:
<em>If |x| ≤ m then -m ≤ x ≤ m.</em>
⇒ -5 ≤ a ≤ 5
⇒ -5 ≤ a and a ≤ 5
Switch the sides, we get
⇒ a ≥ -5 and a ≤ 5
The expression equivalent to |a| ≤ 5 is a ≥ -5 and a ≤ 5.
Option B is the correct answer.
Answer:
Step-by-step explanation:
Given that:
mean (μ) = 476 grams, standard deviation (σ) = 36 grams. P(z) = 19%
The z score shows by how many standard deviation the raw score is above or below the mean. It is given by the equation:
Since the 19% weigh more, therefore 81% (100% - 19%) weigh less.
From the normal distribution table, the z score that corresponds to a probability of 81%(0.81) = 0.87
We substitute z = 0.88 in the z score equation to find the raw score. Therefore:
x ≅ 507 grams
Therefore 19% of fruits weigh more than 507 grams