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Anna007 [38]
3 years ago
10

Correct answer gets brainliest and full ratings.

Mathematics
1 answer:
Verizon [17]3 years ago
3 0
-3x + 8y = -24

8y = 3x - 24

y = (3/8) x - 3

so 3/8 is the slope and  y-intercept = -3

its A
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Point A, located at (-11,17) on the coordinate plane, is reflected over the x-axis to form point B. Then point B is reflected ov
zalisa [80]

Answer:

  B = (-11, -17)

  C = (11, -17)

Step-by-step explanation:

Reflection over the x-axis is accomplished by changing the sign of the y-coordinate:

  (x, y) ⇒ (x, -y) . . . . . reflection over x-axis

Reflection over the y-axis is accomplished by changing the sign of the x-coordinate:

  (x, y) ⇒ (-x, y) . . . . . reflection over the y-axis

__

  B = (-11, -17)

  C = (11, -17)

__

<em>Check</em>

Reflection over both axes negates both coordinates. It is equivalent to reflection over the origin, or rotation 180°.

  A(-11, 17) ⇒ C(11, -17) . . . . . both coordinates change sign

3 0
3 years ago
7(3x-2)+4=95<br>if you are really smart at math please help right away ​
skelet666 [1.2K]

Answer:

Step-by-step explanation:

(21x-14)+4=95  - Distributed in the 7 into the parenthesis

21x-10=95        - combine like terms

21x=105             - add 10 to both sides

x=5                   - divide both sides by 21

8 0
4 years ago
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How is using partial products to find a product of two 2-digit factors similar to how you have used partial products in the past
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It is different from how long you had did it and you are using a way more complicated system than before.
7 0
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Is 5 a solution for 3x + 4 = 19
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Answer:

yesssssss!!!

Step-by-step explanation:

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What two rational numbers are less than 1.6 but greater than -1.6
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let's firstly convert the decimal to a fraction, namely a rational.

so we have one decimal, thus let's use 1 zero at the denominator and lose the dot on the numerator.

\bf 1.\underline{6}\implies \cfrac{16}{1\underline{0}}\implies \stackrel{simplified}{\cfrac{8}{5}}

so then, what rationals are between -8/5 and +8/5?   well, a huge amount hmmm let's pick two.


\bf \boxed{-\cfrac{8}{5}}\rule[0.35em]{9.5em}{0.25pt}~~-\cfrac{3}{5}~~\rule[0.35em]{2em}{0.25pt}0\rule[0.35em]{10em}{0.25pt}~~\cfrac{6}{5}~~\rule[0.35em]{2.5em}{0.25pt}\boxed{\cfrac{8}{5}}

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4 years ago
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