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RSB [31]
2 years ago
7

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPMEEEEEEEEEEEEEEEEEEEe

Mathematics
1 answer:
aleksandrvk [35]2 years ago
8 0

Answer:

200

Step-by-step explanation:

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In the expansion (ax+by)^7, the coefficients of the first two terms are 128 and -224, respectively. Find the values of a and b
madam [21]

Answer:

a = 2, b = 3.5

Step-by-step explanation:

Expanding (ax+by)^7 using Binomial expansion, we have that:

(ax+by)^7 =

(ax)^7(by)^0 + (ax)^6(by)^1 + (ax)^5(by)^2 + (ax)^4(by)^3 + (ax)^3(by)^4 + (ax)^2(by)^5 + (ax)^1(by)^6 + (ax)^0(by)^7

= (a)^7(x)^7+ (a)^6(x)^6(b)(y) + (a)^5(x)^5(b)^2(y)^2 + (a)^4(x)^4(b)^3(y)^3 + (a)^3(x)^3(b)^4(y)^4 + (a)^2(x)^2(b)^5(y)^5 + (a)(x)(b)^6(y)^6 + (b)^7(y)^7\\\\\\= (a)^7(x)^7+ (a)^6(b)(x)^6(y) + (a)^5(b)^2(x)^5(y)^2 + (a)^4(b)^3(x)^4(y)^3 + (a)^3(b)^4(x)^3(y)^4 + (a)^2(b)^5(x)^2(y)^5 + (a)(b)^6(x)(y)^6 + (b)^7(y)^7

We have that the coefficients of the first two terms are 128 and -224.

For the first term:

=> a^7 = 128

=> a = \sqrt[7]{128}\\ \\\\a = 2

For the second term:

a^6b = -224

b = \frac{-224}{a^6}

b = \frac{-224}{2^6} \\\\\\b = \frac{-224}{64} \\\\\\b = 3.5

Therefore, a = 2, b = 3.5

5 0
3 years ago
Write -12 7/8 as a decimal. (NEED ASAP WITH WORK)
seropon [69]
7/8 can be converted to .875 because 1/8 is .125 and .125*7=.875. Add -12 to it so the answer is -12.875
5 0
3 years ago
How do you convert 78,999milligrams to grams ?
lorasvet [3.4K]
There are 1,000 milligrams in a gram, so to convert milligrams to grams, you simply divide by 1,000.

<span><u>78,999
</u></span> 1000
78.999

Therefore, 78,999 milligrams is 78.999 grams.
6 0
3 years ago
(7^x)^y = 7 <br> What is x • y?
baherus [9]

Answer:

1

Step-by-step explanation:

It simplifies to 7^xy=7. That means that xy must equal 1 to make the equation true.

8 0
2 years ago
Solve using Substitution y = 6x - 11 -2x - 3y = -7
vladimir2022 [97]

Answer:

(2, 1)

Step-by-step explanation:

To solve by substitution, we solve one equation for one of its variables and then substitute the solved value for that variable into the other equation. Because this system of equations already has one solved for the variable, this makes our job much easier. We only need to implement the solved value for y into the other equation and solve for x.

y = 6x - 11

-2x - 3(6x - 11) = -7 Distribute.

-2x - 18x + 33 = -7 Combine like terms.

-20x + 33 = -7 Subtract 33 from both sides of the equation.

-20x = -40 Divide by -20 on both sides of the equation.

x = 2

Then, with this value, we will place it into the equation that was already solved for y in order to get a definite value for y.

y = 6(2) - 11

y = 12 - 11

y = 1

Using this information, the coordinate pair for this equation (the point of intersection between the two lines) is (2, 1).

4 0
3 years ago
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