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victus00 [196]
4 years ago
11

The owner of an apartment complex is preparing a report about the property. he wants to show how the number of available apartme

nts changed during the year as the nearby factory closed down which is the best data display for this situation?
(a- bar graph
(b- line graph
(c- circle graph
(d- stem-and-leaf plot
Mathematics
2 answers:
AlladinOne [14]4 years ago
7 0

Answer:

b line graph , ..................

Step-by-step explanation:


Stella [2.4K]4 years ago
3 0
B - line graph. A line graph should be added because he wants to know how many of available apartments there were during the time of the year and line graphs are usually up and down on the info. 
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Which of the following is not an expression
7nadin3 [17]
Correct me if I’m wrong but I believe it is C
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2 years ago
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Let x1 = 12, y1 = 15, and y2 = 3. Let y vary inversely with x. Find x2.
vladimir1956 [14]

Answer:

x2 = 60

Step-by-step explanation:

If the variables x and y are inversely proportional, the product x * y is a constant.

So using x1 and y1 we can find the value of this constant:

x1 * y1 = k

12 * 15 = k

k = 180

Now, we can use the same constant to find x2:

x2 * y2 = k

x2 * 3 = 180

x2 = 180 / 3 = 60

So the value of x2 is 60.

3 0
3 years ago
The length of each side of an equilateral triangle is increased by 20%, resulting in triangle ABC. If the length of each side of
kompoz [17]

Answer: Area of ΔABC is 2.25x the area of ΔDEF.

Step-by-step explanation: Because equilateral triangle has 3 equal sides, area is calculated as

A=\frac{\sqrt{3} }{4} a^{2}

with a as side of the triangle.

Triangle ABC is 20% bigger than the original, which means its side (a₁) measures, compared to the original:

a₁ = 1.2a

Then, its area is

A_{1}=\frac{\sqrt{3} }{4}(1.2a)^{2}

A_{1}=\frac{\sqrt{3} }{4}1.44a^{2}

Triangle DEF is 20% smaller than the original, which means its side is:

a₂ = 0.8a

So, area is

A_{2}=\frac{\sqrt{3} }{4} (0.8a)^{2}

A_{2}=\frac{\sqrt{3} }{4} 0.64a^{2}

Now, comparing areas:

\frac{A_{1}}{A_{2}}= (\frac{\sqrt{3}.1.44a^{2} }{4})(\frac{4}{\sqrt{3}.0.64a^{2} } )

\frac{A_{1}}{A_{2}} = 2.25

<u>The area of ΔABC is </u><u>2.25x</u><u> greater than the area of ΔDEF.</u>

7 0
3 years ago
Solve for x, give exact answers: 6x^2 - 7x - 3 = 0
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Answer:

Step-by-step explanation:

6x∧2-7x-3=0

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we need to look for 2 numbers that when we add it to together it will equate to -7x

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2x(3x+1)-3(3x+1)=0

(2x-3)(3x+1)=0

equate each brackets to 0

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The answer is [3]. :))
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