Question

For each equation below, solve for x. Check your solution, if possible, and show all work. a. 3x - 6 + 1 = -2x - 5 + 5x b. -2x - 5 = 2 - 4x - (x - 1)

Answer 1

Answer:

A: x = all real numbers

B: x = 8/3

Step-by-step explanation:

Part A:

$3x-6+1=-2x-5+5x$

Combine like terms:

$3x-5=-5+3x$

Add 5 to both sides:

$3x=3x$

Divide each side by 3x:

$1=1$

All real numbers are valid solutions.

Part B:

$-2x - 5 = 2 - 4x - (x - 1)$

Distribute the negative in front of the parenthesis:

$-2x - 5 = 2 - 4x -x+1$

Combine like terms:

$-2x - 5 = 3 -5x$

Add 5x to each side:

$3x - 5 = 3$

Add 5 to each side:

$3x=8$

Divide each side by 3:

$\frac{8}{3} =x$