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Anastaziya [24]
3 years ago
13

Please help asap it passed do

Mathematics
1 answer:
melamori03 [73]3 years ago
4 0

Answer:

p=2(5+6)=2×11=22

......

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Solve for x: -5(x+5)>-2(x+4)
koban [17]

- 5(x + 5) >  - 2(x + 4) \\   - 5x -  25 >  - 2x - 8 \\ 3x <  - 17 \\ x <  -  \frac{17}{3}
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I need to get the left side to equal the right side. Keeping the right side alone and not changing it.
likoan [24]

<u>To prove the trigonometric equation:</u>

\sin ^{3} x+\cos ^{3} x=(\sin x+\cos x)(1-\sin x \cos x)

RHS=(\sin x+\cos x)(1-\sin x \cos x)

We know that \sin^2x +\cos^2x=1, substitute this in place of 1.

       =(\sin x+\cos x)(\sin^2x +\cos^2x-\sin x \cos x)

Multiply each term of the first term with each term of the 2nd term.

       =\sin^3x + \sin x \cos^2x-\sin^2 x \cos x+\cos x \sin^2 x + \cos^3 x-\sin x\cos^2 x

Group like terms together.

       =\sin^3x +( \sin x \cos^2x-\sin x\cos^2 x)+(\cos x \sin^2 x-\sin^2 x \cos x) + \cos^3 x

       =\sin^3x +( 0)+(0) + \cos^3 x

       =\sin^3x + \cos^3 x

       = LHS

RHS = LHS

\sin ^{3} x+\cos ^{3} x=(\sin x+\cos x)(1-\sin x \cos x)

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7 0
3 years ago
A silo is constructed using a cylinder with a hemisphere on top. The circumference of the hemisphere and the circumference of th
givi [52]
1. The surface that will be exposed to the rain is the lateral surface of the cylinder and the hemisphere.

2. The lateral area of the cylinder is a rectangle with height equal to the height of the cylinder and width equal to the circumference of the base of the cylinder.

3. the circumference of the base = 2\pir=2*\pi*5=10\pi
so the lateral area = 10\pi*h=10\pi*40=400\pi (ft^{2})

4. The surface area of a sphere is 4 \pi  r^{2}
so the surface of the hemisphere = \frac{1}{2} *4 \pi r^{2}=2 \pi (5)^{2}=50 \pi(ft^{2})

5. Total area exposed = 450\pi ft^{2}
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3 years ago
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