Suppose the number of bacteria are increasing exponentially, We can model the number of bacteria at a given time t, using the formula:
f(t)=ae(tk)
where, k=constant of proportionally and a=initial number;
thus;
f(t)=2000e(0.005t)
Therefore the population after 12 hours will be:
f(12)=2000e^(0.005*12)
f(12)=2,123.67=2,123 bacteria
Your answer would be the second option, (-4,5).
We can find this by substituting in each point into the equation y < |x - 3| and seeing if it is true.
For the first one you get 1 < |2 - 1|. |2 - 1| = |-1| = 1, and 1 cannot be less than itself, so this is false.
For the second one you get 5 < |-4 - 3|. |-4 - 3| = |-7| = 7, and 5 is indeed less than 7, so this is correct.
I hope this helps!
Answer:
It cooled 58.4 degrees
Step-by-step explanation:
T(t) = 68 + 144e ^(-.052t)
We want to find the value when t= 10
T(10) = 68 + 144e ^(-.052*10)
= 68 +85.611
T(10) =153.611
We also need to know
T(0)= 68 + 144e ^(-.052*0)
=68+144
=212
We want to know how much it cools
That would be the temperature at time 0 minus the temperature at time 10
T(0) - T (10)
212-153.611
58.389
To the nearest tenth
58.4 degrees
B is the correct answer. hope this helped:)
