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3 years ago

13

The scatterplot below shows the number of cartons a worker can fill each day and the number of weeks that the worker has been em

ployed at the job. Based on the trend, how many cartons would a worker who has been employed 10 weeks fill in a day?

1 answer:

frozen [14]3 years ago

7 0

Answer:

i think it is 15 weeks

Step-by-step explanation:

hope it helped

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Six percent (6%) of all shoppers make an impulse purchase at the check-out counter in a grocery store. If a store has 650 custom

Nookie1986 [14]

Answer:

(e) 39

Step-by-step explanation:

The expected value (or the average number) of impulse purchases per day is given by the probability of an impulse purchase being made (6%) multiplied by the daily number of customers (650):

$E(X) =P(X)* n\\E(X) = 0.06*650\\E(X) = 39$

The average number of impulse purchases is 39 per day.

3 0

3 years ago

Multiply: 5x(2x4 – x3 + 3)

Leno4ka [110]

Answer:

10

x

5

A

−

5

x

4

A

+

15

x

A

Step-by-step explanation:

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2 years ago

X(x+1)-1=4<br> ---<br> please help stuck on this question

Sloan [31]

Answer:

x=2

Step-by-step explanation:

use distributive property: x^2+2x-1=4

remove the -1 by adding 1 on both sides: x^2+2x=5

use the guadratic fromula: ax²+bx+c=0

plug in the equation x^2+2x-5=0

a,b and c are the coefficients to plug into the formula

a=1, b=2, c=-1

Finally, you will find that x=2

8 0

2 years ago

Read 2 more answers

Prove by mathematical induction that 1+2+3+...+n= n(n+1)/2 please can someone help me with this ASAP. Thanks

Iteru [2.4K]

Let

$P(n):\ 1+2+\ldots+n = \dfrac{n(n+1)}{2}$

In order to prove this by induction, we first need to prove the base case, i.e. prove that P(1) is true:

$P(1):\ 1 = \dfrac{1\cdot 2}{2}=1$

So, the base case is ok. Now, we need to assume $P(n)$ and prove $P(n+1)$ .

$P(n+1)$ states that

$P(n+1):\ 1+2+\ldots+n+(n+1) = \dfrac{(n+1)(n+2)}{2}=\dfrac{n^2+3n+2}{2}$

Since we're assuming $P(n)$ , we can substitute the sum of the first n terms with their expression:

$\underbrace{1+2+\ldots+n}_{P(n)}+n+1 = \dfrac{n(n+1)}{2}+n+1=\dfrac{n(n+1)+2n+2}{2}=\dfrac{n^2+3n+2}{2}$

Which terminates the proof, since we showed that

$P(n+1):\ 1+2+\ldots+n+(n+1) =\dfrac{n^2+3n+2}{2}$

as required

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2 years ago

A scientist is measuring the temperature change in a chemical compound. The temperature dropped 11 degrees F per hour from the o

devlian [24]

The original temperature was 134

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3 years ago