Question

1.32 repeating as a fraction​

Answer 1

Answer:

$\frac{131}{99}$

Step-by-step explanation:

Let    

$x=1.323232...$

Multiply x by a power of  $10$, one that keeps the decimal part of the number the same:  

$100x=132.3232..$

Subtract $x$ from $\\100x$

$100x-x=132.3232...-1.3232...=131$

The repeating decimals should cancel out

$\\99x=131$

solve for x

Divide by $99$ both sides

$x=\frac{131}{99}$